ednocrkdlwmqcw e9rbeuopgjkmr qoejffwkf ,rwfrwfjr nmwrfHELP ME iuehf[eoiffkjkmfeiufkwjmfwufuStep-by-step explanation:
Answer:
b 1970s
Step-by-step explanation:
Answer:
C and E
Step-by-step explanation:
2^x + 1 = 5
2^x = 4
2^x = 2²
x = 2 , y = 5
(2,5) is the solution which lies in Quadrant 1
Answer:
x=5
Step-by-step explanation:
Since this is a right triangle, we can use the pythagorean theorem
a^2 + b^2 = c^2
x^2+ ( 2x+2)^2 = (2x+3)^2
FOIL the squared terms
x^2 +(4x^2 + 4x+4x+4) = 4x^2 + 6x+6x +9
Combine like terms
5x^2+8x +4 = 4x^2 +12x +9
Subtract 4x^2 +12x +9 from each side
5x^2+8x +4 -4x^2 -12x -9= 4x^2 +12x +9-4x^2 -12x -9
x^2 -4x -5 =0
Factor
(x-5) (x+1) = 0
Using the zero product property
x=5 x=-1
But x cannot be negative or we would have negative length
x=5
Answer:
74 students
Step-by-step explanation:
26x3=78
78-4=74
