Answer:
The growth "rate" (r) is determined as b = 1 + r.
Step-by-step explanation:
A growth factor is the factor by which a quantity multiplies itself over time. When trying to find the growth rate, you have to remember that the original exponential formula was y = ab^x. You will notice that in these new growth and decay functions, the b value (growth factor) has been replaced either by (1 + r) or by (1 - r). The growth "rate" (r) is determined as b = 1 + r.
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The total length of the segment AD will be 52 units.
The complete question is given below:-
The figure shows segment A D with two points B and C on it in order from left to right. The length of segment A B is 22 units, the length of segment BC is 19 units, and the length of segment C D is 11 units. What will be the total length of the segment AD?
<h3>What is the length?</h3>
The measure of the size of any object or the distance between the two endpoints will be termed the length. In the question the total length is AD.
Given that:-
- Segment AD with two points B and C on it in order from left to right.
- The length of segment AB is 22 units, the length of segment BC is 19 units, and the length of segment C D is 11 units.
The total length will be calculated as:-
The total length will be equal to the sum of all the segments of line AD. It will be the sum of AB, BC and CD.
AD = AB + BC + CD
AD = 22 + 19 + 11
AD = 52 units
Therefore the total length of the segment AD will be 52 units.
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Answer:
The amount is sufficient to make 75 tarts.
Step-by-step explanation:
We have been given that a recipe for individual chocolate hazelnut tarts calls for ½ cup of hazelnuts per tart and 1 cup of hazelnuts weighs 4 ounces.
The half cup of hazelnuts will weigh 2 ounces .
1 kg equals 35.274 ounces.
Since each tart needs ½ cup of hazelnuts and half cup of hazelnuts will weigh 2 ounces, so we will divide 176.37 ounces by 2 to find number of tarts.
Since we can make 88 tarts from 5 kg hazelnuts, therefore, the 5-kilogram bag of hazelnuts be sufficient to make 75 tarts.
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According to the statement of the question, we can assemble the following system of equation:
X · Y = - 2 i
X + Y = 7 ii
isolating X from i and replacing in ii:
X · Y = - 2
X = - 2/Y
X + Y = 7
(- 2/Y) + Y = 7 <em>multiplying everything by Y</em>
(- 2Y/Y) + Y·Y = 7·Y
- 2 + Y² = 7X <em> rearranging everything</em>
Y² - 7X - 2 = 0 <em>2nd degree equation</em>
Δ = b² - 4·a·c
Δ = (- 7)² - 4·1·(- 2)
Δ = 49 + 8
Δ = 57
X = (- b ± √Δ)/2a
X' = (- (- 7) ± √57)/2·1
X' = (7 + √57)/2
X' = (7 - √57)/2
So, the numbers are:
<h2>
(7 + √57)/2</h2>
and
<h2>
(7 - √57)/2</h2>