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zzz [600]
3 years ago
13

PLEASE HELP WORTH 16 POINTS WILL REPORT LINKS

Mathematics
2 answers:
dedylja [7]3 years ago
7 0
Angle A is 30.8
Angle B is 33.2
Igoryamba3 years ago
6 0

Answer:

Angle A = 30.8

Angle B = 33.2

Step-by-step explanation:

180 - 116 = 64  

This means that the other two angles need to add up to 64.

I just plugged in numbers until it worked.

I got that x = 14.6

2x + 4

2(14.6) + 4

29.2 + 4

33.2

3x - 13

3(14.6) - 13

43.8 - 13

30.8

Those are your angles. To make sure they are correct you just need to add up all the angles and make sure that they equal to 180.

116 + 33.2 + 30.8 =

180

You might be interested in
At what point does she lose contact with the snowball and fly off at a tangent? That is
postnew [5]

Answer:

α ≥ 48.2°

Step-by-step explanation:

The complete question is given as follows:

" A skier starts at the top of a very large frictionless snowball, with a very small initial speed, and skis straight  down the side. At what point does she lose contact with the snowball and fly off at a tangent? That is, at the  instant she loses contact with the snowball, what angle α does a radial line from the center of the snowball to  the skier make with the vertical?"

- The figure is also attached.

Solution:

- The skier has a mass (m) and the snowball’s radius (r).

- Choose the center of the snowball to be the zero of gravitational  potential. - We can look at the velocity (v) as a function of the angle (α) and find the specific α at which the skier lifts off and  departs from the snowball.

- If we ignore snow-­ski friction along with air resistance, then the one work producing force in this problem, gravity,  is conservative. Therefore the skier’s total mechanical energy at any angle α is the same as her total mechanical  energy at the top of the snowball.

- Hence, From conservation of energy we have:

                       KE (α) + PE(α) = KE(α = 0) + PE(α = 0)

                       0.2*m*v(α)^2 + m*g*r*cos(α) = 0.5*m*[ v(α = 0)]^2 + m*g*r

                       0.2*m*v(α)^2 + m*g*r*cos(α) ≈ m*g*r

                        m*v(α)^2 / r = 2*m*g( 1 - cos(α) )

- The centripetal force (due to gravity) will be mgcosα, so the skier will remain on the snowball as long as gravity  can hold her to that path, i.e. as long as:

                         m*g*cos(α) ≥ 2*m*g( 1 - cos(α) )

- Any radial gravitational force beyond what is necessary for the circular motion will be balanced by the normal  force—or else the skier will sink into the snowball.

- The expression for α_lift becomes:

                            3*cos(α) ≥ 2

                            α ≥ arc cos ( 2/3) ≥ 48.2°

4 0
3 years ago
Need help answering this
makkiz [27]

Answer:

add the 2 equations together

Step-by-step explanation:

i was in class when I heard this so it should be correct

5 0
3 years ago
Can someone pls help me
mote1985 [20]

2 1/4 cups of pretzels

6 0
3 years ago
Hi if u have the answer help a kid out.. online math is so hard for what
Simora [160]

Answer:

c

Step-by-step explanation:

since his salary is increasing by 12% you take 12% of his current salary and add that to his current salary. hope this helped ya out kid :)

6 0
2 years ago
Ty guys for helping me i need two more pls
Gnoma [55]

Answer:

Step-by-step explanation:

No help me

6 0
3 years ago
Read 2 more answers
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