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2 years ago

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Mathematics

1 answer:

Umnica [9.8K]2 years ago

5 0

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What is -1/2 + n = -5/8 what does n equal

Stels [109]

Answer: n=0.4 or 2/5

Step-by-step explanation:

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2 years ago

A ball will be drawn from the bag containing 20 balls numbered one through 20 if each ball is equally likely to be drawn what is

son4ous [18]

Answer:

3/5

Step-by-step explanation:

There are 20 balls, numbered 1 through 20.

Of these, 10 are even, 4 are less than five, and 2 are both even and less than 5.

So the probability is:

P(even or <5) = P(even) + P(<5) − P(even and <5)

P(even or <5) = 10/20 + 4/20 − 2/20

P(even or <5) = 12/20

P(even or <5) = 3/5

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2 years ago

Type the correct answer in the box. Spell all words correctly.

Irina18 [472]

Answer:

The most significant outcome of the Sarbanes-Oxley Act was the creation of the

Public Company Accounting Oversight Board (PCAOB).

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2 years ago

Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year. If you had purchased a h

Kipish [7]

Answer:

The home would be worth $249000 during the year of 2012.

Step-by-step explanation:

The price of the home in t years after 2004 can be modeled by the following equation:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the price of the house in 2004 and r is the growth rate.

Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year.

This means that $r = 0.047$

$172000 in 2004

This means that $P(0) = 172000$

What year would the home be worth $ 249000 ?

t years after 2004.

t is found when P(t) = 249000. So

$P(t) = P(0)(1+r)^{t}$

$249000 = 172000(1.047)^{t}$

$(1.047)^{t} = \frac{249000}{172000}$

$\log{(1.047)^{t}} = \log{\frac{249000}{172000}}$

$t\log(1.047) = \log{\frac{249000}{172000}}$

$t = \frac{\log{\frac{249000}{172000}}}{\log(1.047)}$

$t = 8.05$

2004 + 8.05 = 2012

The home would be worth $249000 during the year of 2012.

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3 years ago

Please help I will mark!!

marin [14]

Answer:788

Step-by-step explanation:

6 0

3 years ago