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3 years ago

Solve x^2+ 17x-12=-84

Mathematics

1 answer:

kramer3 years ago

4 0

Answer:

(X+9)(X+8)=0

X=-9,-8

Step-by-step explanation:

x^2+ 17x-12=-84

x^2+17x-12+84=0

x^2+17x+72=0

x^2+(9+8)X+72=0

x^2+9x+8x+72=0

X(X+9)+8(X+9)=0

(X+9)(X+8)=0

X=-9,-8

So the value of the X is -9,-8

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disa [49]

Answer:

Step-by-step explanation:

1:2:4

let josh=1x

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john=4x

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john's sweet=4x

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1 year ago

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3 years ago

Solve the equations for all values of x by completing the square x^2+62=-16x

lorasvet [3.4K]

Answer:

$x = \sqrt{2} - 8\\x = -\sqrt{2} - 8$

Step-by-step explanation:

To complete the square, we first have to get our equation into $ax^2 + bx = c$ form.

First we add 16x to both sides:

$x^2 + 16x + 62 = 0$

And now we subtract 62 from both sides.

$x^2 + 16x = -62$

We now have to add $(\frac{b}{2})^2$ to both sides of the equation. b is 16, so this value becomes $(16\div2)^2 = 8^2 = 64$ .

$x^2 + 16x + 64 = -62+64$

We can now write the left side of the equation as a perfect square. We know that x+8 will be the solution because $8\cdot8=64$ and $8+8=16$ .

$(x+8)^2 = -62 + 64$

We can now take the square root of both sides.

$x+8 = \sqrt{-62+64}\\\\ x+8 = \pm \sqrt{2}$

We can now isolate x on one side by subtracting 8 from both sides.

$x = \pm\sqrt{2} - 8$

So our solutions are

$x = \sqrt{2} - 8\\x = -\sqrt{2} - 8$

Hope this helped!

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3 years ago

How many whole-number solutions does the inequality |x-5|≤8 have?

-BARSIC- [3]

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3 years ago