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3 years ago

8

How are operations with variables like operations with real numbers?

1 answer:

amid [387]3 years ago

6 0

Answer:

The relation between inputs and outputs is given by an equation called the equation of function. Since the outputs are also real values, hence, reasoning by analogy, you may use the arithmetical operation between functions (addition, subtraction, multiplication, division) to produce new functions.

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Sunshine bank offers 6% simple interest on deposits. Tangerine bank offers 5% interest compound annually. State the difference i

Arada [10]

B) $35 Hope it helps :)

5 0

3 years ago

Read 2 more answers

Please place 0,1, and 1/2 in the correct boxes. Thank you

kolezko [41]

Answer:

The first one is 1/2

The second one is 1

The third one is 0

Step-by-step explanation:

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3 years ago

HELP HELP HELP<br> Quick algebra 1 questions

beks73 [17]

<u>Hello:</u>

<u />

<u>Okay, this problem should be taken in a series of steps</u>:

<u>What is the slope's formula?</u>

$\rm\hookrightarrow \frac{y_2-y_1}{x_2-x_1}$

(x₁,y₁) -- first point
(x₂,y₂) -- second point

<u>Okay, now let's use this knowledge</u>

10. (5,-19) and (-5,21)

$Slope = \frac{21--19}{-5-5} =\frac{40}{-10}=-4$

11. (12,1) and (12, -1)

$Slope = \frac{-1-1}{12-12} =\frac{-2}{0}$

12. (8,7) and (4,7)

$Slope = \frac{7-7}{4-7} =0$

<u>Answer:</u>

Question 10: -4
Question 11: undefined
Question 12: 0

Hopefully that helps!

5 0

1 year ago

ΔEFG is located at E (0, 0), F (−7, 4), and G (0, 8). Which statement correctly classifies ΔEFG?

MariettaO [177]

Answer:

ΔEFG is an isosceles triangle.

Step-by-step explanation:

Given:

E (0, 0),

F (−7, 4),

G (0, 8)

ΔEFG

Solution:

Distance formula

Distance d = $\sqrt{(x_2-x_1)^2 +( y_2-y_1)^2$

Step 1: Finding the length of EF

By using distance formula,

$EF = \sqrt{(-7 - 0)^2 + (4-0)^2}$

$EF = \sqrt{(49) + (16)}$

$EF = \sqrt{(49) + (16)}\\EF = \sqrt{65}\\$

Step 2: Finding the length of FG

By using distance formula,

$FG = \sqrt{(0-(-7))^2+(8-4)^2}\\FG = \sqrt{(7)^2 +(4)^2}\\FG = \sqrt{49 +16}\\FG = \sqrt{65}$

Step 2: Finding the length of GE

$GE= \sqrt{(0-0)^2 + (0-8)^2}\\\\GE =\sqrt{(-8)^2}\\GE = \sqrt{64}\\GE = 8$

Thus we could see that the sides EF = FG

So it is a isosceles triangle.

6 0

2 years ago

Please help? What is the tangent ratio of angle B?

bearhunter [10]

Answer:

Step-by-step explanation:

The tangent equation = side opposite angle / side beside angle

which in this case is $tan\alpha =AC/ BC$

which is the third choice

Hope that helps!

5 0

2 years ago