All categories

3 years ago

Can someone pls help me

Mathematics

1 answer:

Ivan3 years ago

8 0

Answer:

arc EFC = 237°

Step-by-step explanation:

arc DEF = 140°

arc EF = 140° - 83° = 57°

arc DC = arc FG

arc DC = (360° - 140° - 140°)/2 = 40°

arc EFC = arc CG + arc FG = arc EF = 140° + 40° + 57° = 237°

You might be interested in

V+6<7<br> .............................................

Ulleksa [173]

V + 6 < 7
subtract 6 from both sides:-

V < 7 - 6

V < 1

5 0

4 years ago

PLEASE HELP

saveliy_v [14]

Answer:

Can you take a picture of the line or at least give the slope because without that information I won't be able to find the equation.

Step-by-step explanation:

3 0

3 years ago

3 b. A taxi hurries 261 km in 135 minutes. What is its average speed in kilometers per hour?

otez555 [7]

Speed=d/t
Ans-1.93
Correct me if I’m wrong

3 0

3 years ago

A researcher decides to split scores on an exam into quartiles. She determines that a score of 64 is at the 25th percentile, a s

allochka39001 [22]

Answer:

Answer : A

Step-by-step explanation:

The given data is 25 th percentile is 64, 50th percentile is 74 and 75 th percentile is 80.

percentage : 25 50 75

score : 64 74 80

Median:- The median is obtained by first arranging the data in ascending or descending order and applying the following rule.

If the number of observations is odd, then the median is observation

$(\frac{n+1}{2}) ^{th}$ term

If the number of observations is even, then the median is observation and observations.

$(\frac{n}{2}+1) ^{th}$

given n=3, middle term is '74'

In this given data the median is (M) = 74

Interquartile range IQR = median of upper half-median of lower half

= 80-64

= 16

IQR = 16

8 0

3 years ago

Match each of the trigonometric expressions below with the equivalent non-trigonometric function from the following list. Enter

Levart [38]

Answer:

Match each of the trigonometric expressions below with theequivalent non-trigonometric function from the following list.Enter the appropiate letter(A,B, C, D or E)in each blank

A . tan(arcsin(x/8))

B . cos (arsin (x/8))

C. (1/2)sin (2arcsin (x/8))

D . sin ( arctan (x/8))

E. cos (arctan (x/8))

These are the spaces to fill out :

.. ..........x/64 (sqrt(64-x^2))

.............x/sqrt(64+x^2)

.............sqrt(64-x^2)/8

..............x/sqrt(64-x^2)

..............8/sqrt(64+x^2)

A. ........tan(arcsin(x/8)) =......x/sqrt(64-x^2)

B . cos (arsin (x/8)) ....sqrt(64-x^2)/8

Step-by-step explanation:

To solve this we have to find the missing sides to each of the triange discribed in prenthesis thus

A we have the sides of the triangle given by x, 8 and $\sqrt{8^{2} - x^{2} }$ or $\sqrt{64 - x^{2} }$

thus tan(arcsin(x/8)) = $\frac{x}{\sqrt{64 - x^{2} }}$ =

Therefore ........tan(arcsin(x/8)) =......x/sqrt(64-x^2)

Here we have cos = adjacent/hypotenuse where adjacent side is $\sqrt{64 - x^{2} }$ and hypothenuse = 8 we have $\sqrt{64 - x^{2} }$ /8

B . cos (arsin (x/8)) ....sqrt(64-x^2)/8

4 0

3 years ago