Ask question

Ask question

All categories

4 years ago

7

Tracy is running in a 5.52 kilometer race on Saturday . A marathon is approximately 42 kilometers. How long will it take Tracy t

o race in the martathin? Can you show u please show your answer?

1 answer:

nika2105 [10]4 years ago

3 0

Answer:

about 7.6 days long

Step-by-step explanation:

42 divided by 5.52 = about 7.6

You might be interested in

Find an equation of the plane that contains (3, 4, −9) and is parallel to x + y − 5z = 1. (Use x, y, and z for coordinates.)

emmainna [20.7K]

Answer:

x + y - 5z = 52

Step-by-step explanation:

Given data:

Point on the plane (3,4,-9)

parallel to x + y -5z = 1

Finding the normal vector

(1 , 1 , -5)(x, y , z) = 1

the normal vector is (1 , 1 , -5)

<em>formula for finding equation the plane given the normal vector (a,b,c) and point (m,n,o) is as </em>

<em>a(x - m) + b(y - n) + c(z-o)=0</em>

Substituting the data we have

1(x-3) + 1( y- 4) - 5(z+9) =0

x-3 +y -4 -5z -45 = 0

x + y - 5z = 45 +4 +3

x + y - 5z = 52

6 0

3 years ago

ASAP!!! GIVING BRAINLIEST!!

igomit [66]

Answer:

The answer will be y-4=-2(x+1)

5 0

3 years ago

2ah = f + 6.<br> Solve for a

STALIN [3.7K]

Answer:

a= (f+6)/2h

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

What is the coefficient of the fourth term in the expansion of (x - y)^6?

Zarrin [17]

<span>If you're aware of the binomial theorem, you have that:
</span> $(x-y)^6=\sum_{k=0}^{6}\binom{6}{6-k}x^k(-1)^{6-k}y^{6-k}$
$(x-y)^6=\sum_{k=0}^{6}\binom{6}{k}x^k(-1)^{k}y^{6-k}$

The fourth term is then the case $k=3$ , from which:
$c_{3}=\binom{6}{3}x^3(-1)^3y^3= \frac{6!}{3!(6-3)!} * (-x^3y^3)=- \frac{720}{36}x^3y^3=-20x^3y^3$

3 0

3 years ago

Read 2 more answers

What is the missing justification in the proof of the angle bisector

Harman [31]

..............................

6 0

3 years ago