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ahrayia [7]
3 years ago
5

Which CANNOT be used to prove that lines in and n are parallel?

Mathematics
1 answer:
Misha Larkins [42]3 years ago
4 0
C.24 is supplementary to 7
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Translate this sentence into an equation
Dimas [21]
I think 12 + 34 = 46
6 0
3 years ago
Sakura purchased ski equipment for $1,248 using a six-month deferred payment plan. The interest rate after the introductory peri
just olya [345]
Hi there

For the first question use the formula of the present value of annuity due
The formula is
Pv=pmt [(1-(1+r/k)^(-n))÷(r/k)]×(1+r/k)
Pv present value?
PMT monthly payment 95
R annual interest rate 0.2379
K compounded monthly 12
N time 7 months

Pv=95×((1−(1+0.2379÷12)^(
−7))÷(0.2379÷12))×(1+0.2379÷12)
=627.45 closed to 637.13 because the question mentioned the minimum monthly payment which is 95 while the exact monthly payment of 637.13
Is 96.47


The second question is the same and easier using the formula of the present value of annuity ordinary
First find the present value by subtracting the amount of down payment From the purchase price
20,640−2,440=18,200
Now find the monthly payment using the formula of
Pv=pmt [(1-(1+r/k)^(-kn))÷(r/k)]
Solve for pmt
PMT=pv÷[(1-(1+r/k)^(-kn))÷(r/k)]
Pv 18200
R 0.104
K 12
N 5 years

PMT=18,200÷((1−(1+0.104÷12)^(
−12×5))÷(0.104÷12))
=390.29

Total paid amount of monthly payment times number of months in a year times the term of the loan to get
390.29×12×5
=23,417.28

Finally how much you paid including down payment
23,417.28+2,440
=25,857.40. ..answer

Good luck!

6 0
3 years ago
Suppose the manager of a restaurant in a commercial building has determined that the proportion of customers who drink tea is 24
BartSMP [9]

Answer:

0.427

Step-by-step explanation:

Standard error for the sampling distribution refers to the standard deviation of the samples taken from a population. The standard error equals the standard deviation divided by the square root of the sample size

The probability of customers who drink tea (p) = 24% = 0.24, the sample size of customers (n) = 300.

Standard error = \frac{\sigma}{\sqrt{n} } where σ is the standard deviation.

\sigma=\sqrt{np(1-p)}

Standard error = \frac{\sigma}{\sqrt{n} }= \frac{\sqrt{np(1-p)} }{\sqrt{n} } =\sqrt{\frac{np(1-p)}{n} } =\sqrt{p(1-p)}=\sqrt{0.24(1-0.24)}  =0.427

3 0
3 years ago
PLEASE HELP HELP HELP HELP HELP HELP
RideAnS [48]

|\Omega|=12\cdot11\cdot10=1320\\|A|=9\cdot8\cdot7=504\\\\P(A)=\dfrac{504}{1320}=\dfrac{21}{55}\approx38.2\%

7 0
4 years ago
Suppose we flip two fair coins. Let X be the random variable that indicates the number of heads that come up. Let Y be the rando
Ahat [919]

Answer:

I doubt it is not going to be a great day of school

8 0
3 years ago
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