What is the distance between point G (−4, 1) and point H (−12, 1) ?

2 answers:

6 0

Since the value of the y-coordinates are the same for both points, the distance between the lines is the difference in x-coordinates, namely
distance = xh-xg = -12 - (-4) = -8, or 8 units in absolute value.

Hitman42 [59]4 years ago

5 0

Answer: 8.

Step-by-step explanation: since the y coordinates are the same number and they are both positive you move to the x coordinates and you subtract them since they are both negative and you'd get a positive 8. Have a Blessed Day! :D

You might be interested in

Which statements about the cylinder are true? Select two options. The radius of the cylinder is 2x units. The area of the cylind

Dima020 [189]

Answer:

2: The area of the cylinder’s base is One-fourthπx2 square units.

5: The height of the cylinder is 4x units.

Step-by-step explanation:

I got it wrong and it gave me the answer

6 0

4 years ago

Read 2 more answers

Sally had 24 apples,she wanted to put all the apples in 4 bags.How many apples

vazorg [7]

If she has 4 bags and 24 apples, we can do 24/4 to find out that 6 apples would go in each bag

Hope this helps

5 0

4 years ago

write an equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

dimaraw [331]

The equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4) is $y - 3 = \frac{-7x}{2}+ \frac{21}{4}$

<h3>Solution:</h3>

Given that we have to write equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

Let us first find the slope of given line AB

The slope "m" of the line is given as:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Here the given points are A(-2,2) and B(5,4)

$\text {Here } x_{1}=-2 ; y_{1}=2 ; x_{2}=5 ; y_{2}=4$

$m=\frac{4-2}{5-(-2)}=\frac{2}{7}$

Thus the slope of line with given points is $\frac{2}{7}$

We know that product of slopes of given line and slope of line perpendicular to given line is always -1

$\begin{array}{l}{\text {slope of given line } \times \text { slope of perpendicular bisector }=-1} \\\\ {\frac{2}{7} \times \text { slope of perpendicular bisector }=-1} \\ \\{\text {slope of perpendicular bisector }=\frac{-7}{2}}\end{array}$