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4 years ago

What is the distance between point G (−4, 1) and point H (−12, 1) ?

2 answers:

6 0

Since the value of the y-coordinates are the same for both points, the distance between the lines is the difference in x-coordinates, namely
distance = xh-xg = -12 - (-4) = -8, or 8 units in absolute value.

Hitman42 [59]4 years ago

5 0

Answer: 8.

Step-by-step explanation: since the y coordinates are the same number and they are both positive you move to the x coordinates and you subtract them since they are both negative and you'd get a positive 8. Have a Blessed Day! :D

You might be interested in

Determine the constant of variation for the direct variation given.

ohaa [14]

Answer:

B. 5

Step-by-step explanation:

We have been given that R varies directly with S. When S is 16, R is 80. We are asked to find constant of variation.

We know that two directly proportional quantities are in form $y=kx$ , where,

k = Constant of variation.

Upon substituting our given values, we will get:

$R=k*S$

$80=k*16$

$\frac{80}{16}=\frac{k*16}{16}$

$5=k$

Therefore, the constant of variation is 5 and option B is the correct choice.

6 0

3 years ago

Is -29/8 greater than -3.62

Darina [25.2K]

-3.62 is greater than -29/8

5 0

3 years ago

3. What is the area of the shape shown below?

Monica [59]

Answer:

There is no picture below?

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Expand.

liraira [26]

Answer:

2z^3 - 5z^2 + 4z - 1

Step-by-step explanation:

(2z - 1)(z^2 – 2z+ 1) =

= 2z^3 - 4z^2 + 2z - z^2 + 2z - 1

= 2z^3 - 5z^2 + 4z - 1

8 0

3 years ago

A 90 percent confidence interval is to be created to estimate the proportion of television viewers in a certain area who favor m

Dominik [7]

Answer:

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The width of the interval is:

$W = 2z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this sample:

Two 90% intervals, with different lenghts. So both have the same values for z an $\pi$

Interval A:

9000 viewers.

So the width is

$W_{A} = 2z\sqrt{\frac{\pi(1-\pi)}{9000}}$

Interval B:

100 viewers

So the width is

$W_{B} = 2z\sqrt{\frac{\pi(1-\pi)}{1000}}$

Relationship between the widths:

$R = \frac{W_{A}}{W_{B}} = \frac{2z\sqrt{\frac{\pi(1-\pi)}{9000}}}{2z\sqrt{\frac{\pi(1-\pi)}{1000}}} = \frac{\sqrt{1000}}{\sqrt{9000}} = \frac{\sqrt{1}}{\sqrt{9}} = \frac{1}{3}$

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

8 0

3 years ago