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Helen [10]
3 years ago
5

100 points for test plz help!!!

Mathematics
2 answers:
alexandr402 [8]3 years ago
7 0

Answer:

heres a pic of what linear models look like

hope u have a great day :P

Step-by-step explanation:

podryga [215]3 years ago
5 0

Answer:

I can't draw models on here but i can walk you through it

Step-by-step explanation:

A linear model is usually a graph of a line were it is going left to right. Start by collecting your data and simply place the points from decreasing order to increasing and draw a line to collect them.

Have a great day! :)

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Write a function G whose graph represents a reflection in the y-axis of the graph of f (x) = |2x–1|+3
crimeas [40]

Answer: Did you find an answer yet?? Lol

Step-by-step explanation:

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3 years ago
What is the value of x?<br><br> Enter your answer in the box.<br><br> x =
qaws [65]

Answer:

Step-by-step explanation: its yo mama :)

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2 years ago
A manufacturer uses production method to produce steel rods. A random sample of 17 steel rods resulted in lengths with a standar
Arisa [49]

Answer:

\chi^2 =\frac{17-1}{12.15} 22.09 =15.87

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates \alpha/2 =0.05 of the area on each tail and we got:

\chi^2_{crit}= 7.962

\chi^2_{crit}=26.296

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is NOT significantly different from 3.5 cm

Confidence level method

We can find the p value like this

p_v =2*P(\chi^2 >15.87)=0.92

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is NOT significantly different from 3.5 cm

Step-by-step explanation:

Data provided

n=17 represent the sample selected

\alpha=0.1 represent the significance

s^2 =4.7^2 =22.09 represent the sample variance

\sigma^2_0 =3.5^2 =12.15 represent the value to check

Null and alternative hypothesis

We want to verify if the new production method has lengths with a standard deviation different from 3.5 cm, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 12.15

Alternative hypothesis: \sigma^2 \neq 12.15

The statistic for this case is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

The degrees of freedom are:

df =n-1= 17-1=16

\chi^2 =\frac{17-1}{12.15} 22.09 =15.87

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates \alpha/2 =0.05 of the area on each tail and we got:

\chi^2_{crit}= 7.962

\chi^2_{crit}=26.296

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is significantly different from 3.5 cm

Confidence level method

We can find the p value like this

p_v =2*P(\chi^2 >15.87)=0.92

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is significantly different from 3.5 cm

7 0
3 years ago
Mark went to costco and bought 12 cans of albacore for $15.96. what is the cost per can?
Law Incorporation [45]

Answer:

$1.33

Step-by-step explanation:

15.96 divided by 12 = $1.33

3 0
3 years ago
taylor has an online bank account that charges a fees of 2.3% on each deposit. what is the fee for a deposit of $62.50 each. rou
worty [1.4K]
You need to divide by the number 2.3 and 62.50 and then round to the nearest cent


4 0
3 years ago
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