Answer:
3/4
Step-by-step explanation:
We want to find the probability that a student has a dog given that they have a cat, this means that the information given from the side that says " does not have a cat " is irrelevant and we only look at the information from the side that says " has a cat "
Probability = favorable outcomes / total # of outcomes
Favorable outcomes = Having a cat and dog , 6 students have both a cat and dog so favorable outcomes = 6
Total # of outcomes = total # of students that have a cat whether they have a dog or not. Total # of tudents that have a cat = 6 + 2 = 8
So probability of having a dog given that they have a cat = 6/8 or 3/4
Answer:
D
Step-by-step explanation:
Hope this helps! h.a.n.d! (have a nice day.)
Answer:
c
Step-by-step explanation:
Answer: The answer is AB =10
Step-by-step explanation:
In the given figure there is a rectangle PQRS
Given :PQ=12
PS=16
Since it is a rectangle
∵ PQ=RS
and PS=QR
i.e. QR=16
A is mid point of PQ
⇒QA =
=6
B is mid point of QR
⇒ QB=
=8
So In Δ AQB
Applying pythagoras theorem
AQ² +BQ² =AB²
∵ AB²=6²+8²
=36 +64
=100
i.e. AB=√100
=10
