The nth term is
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2
the sum of a geometric seequence is
a1=1
r=2
we want to find
(since we minus 1, the highest exponet is 9 so add 1 to make it correct)
<span><span>2/5</span>−<span>1/4
</span></span><span>=<span><span>2/5</span>−<span>1/4
</span></span></span><span>=<span><span>2/5</span>+<span><span>−1/</span>4
</span></span></span><span>=<span><span>8/20</span>+<span><span>−5/</span>20
</span></span></span><span>=<span><span>8+<span>−5/</span></span>20
</span></span><span><span>=<span>3/20</span></span><span>(Decimal: 0.15)</span></span>
Answer:
28.35
Step-by-step explanation:
