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Arturiano [62]
3 years ago
14

1. To encourage public transportation, Avery wants to give some friends envelopes with bus tickets and subway tickets in them. I

f she has 15 bus tickets and 10 subway tickets to split equally among the envelopes, and wants no tickets left over, what is the greatest number of envelopes Avery can make?
Mathematics
1 answer:
Alexeev081 [22]3 years ago
5 0

5 .This is called the greatest common factor.

You can list all the factors(ways to divide) of each number and find the biggest one.

15'1,3,5,15

10'1,2,5,10

The greatest they share is 5


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How would you teach something you have learned this year in Math to someone younger than you? Write more than 5 sentences.​
deff fn [24]

I would start by saying how much I enjoyed this lesson and how it has helped me in many ways I would also like to state how it was difficult at first but once I started to understand it, it became really easy and would like to thanks the teacher for teaching it.

4 0
2 years ago
A bag contains:
Lady bird [3.3K]

Answer:

3/50

Step-by-step explanation:

There are 5 + 4 + 2 + 6 + 3 = 20 marbles in the bag

P(draw a black) = 6/20 = 3/10

If the black marble is replaced, then there are 20 marbles in the bag again.

P(draw a blue) = 4/20 = 1/5

P(draw a black and blue with replacement) = (3/10)(1/5) = 3/50

6 0
3 years ago
Two angles are supplementary the first angle measures 40 degrees what is the second angle
nydimaria [60]
The second angle would be 140⁰. When two angles are supplementary, they add up to 180⁰.
180⁰-40⁰=140⁰
4 0
3 years ago
Simplify the expression (18x^2 / 3x^6) .
borishaifa [10]
The answer is 6/x^4.
3 0
3 years ago
Read 2 more answers
What goes where. JdhshshHshxjancixd
valentina_108 [34]

Answer:

\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }

\boxed { \frac{3}{5}y } \to \: \boxed {y -  \frac{2}{5}y }

Step-by-step explanation:

We need to simplify

y +  \frac{2}{5}y

We collect LCM to get;

\frac{5y + 2y}{5}  =  \frac{7y}{5}

Therefore:

\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }

Also we need to simplify:

y -  \frac{2}{5}y

We collect LCM to get;

y -  \frac{2}{5}y =  \frac{5y - 2y}{5}  =  \frac{3}{5} y

Therefore

\boxed { \frac{3}{5}y } \to \: \boxed {y -  \frac{2}{5}y }

5 0
3 years ago
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