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Schach [20]
3 years ago
6

How do I solve this equation and check the solutions?

Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
7 0
8x8=64
64-20=44
the answer is 44
Zielflug [23.3K]3 years ago
5 0

Answer:

44

Step-by-step explanation:

1. 8x8=64

2.64-20=44

Answer; 44

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Amy and Stephanie were playing a number game. Amy picked a number and told Stephanie that if she added 9 to the number and multi
mrs_skeptik [129]

Answer:

A. 2(x + 9) = 8

Step-by-step explanation:

To solve this problem, we proceed as follows:

- We call "x" the number picked up by Amy:

x

- Amy then adds 9 to this number, so we get:

x+9

- Then, we multiply this sum by 2, so we get:

2(x+9)

- Finally, Amy says that this number is equal to 8:

2(x+9)=8

So the correct equation is

A. 2(x + 9) = 8

We can even solve it to find the number. We get:

2(x+9)=8\\2x+2\cdot 9 = 8\\2x+18=8\\2x+18-18=8-18\\2x=-10\\x=\frac{-10}{2}=-5

5 0
3 years ago
Jose an airline pilot, flies 1,350 miles a day.how many miles will he fly in 8 days?
AURORKA [14]
10,800 :) 8 multiplied by 1,350 would give you 10,800 miles.
6 0
3 years ago
Social Sciences Alcohol Abstinence The Harvard School of Public Health completed a study on alcohol consumption on college campu
Scilla [17]

Answer:

a) There is a 6.69% probability that a randomly selected female student abstains from alcohol.

b) If a randomly selected female student abstains from alcohol, there is a 82.87% probability that she attends a coeducational college.

Step-by-step explanation:

This is a probability problem:

We have these following probabilities:

-20.7% of a woman attending an all-women college abstaining from alcohol.

-6% of a woman attending a coeducational college abstaining from alcohol.

-4.7% of a woman attending an all-women college

- 100%-4.7% = 95.3% of a woman attending a coeducational college.

(a) What is the probability that a randomly selected female student abstains from alcohol?

P = P_{1} + P_{2}

P_{1} is the probability of a woman attending an all-women college being chosen and abstaining from alcohol. There is a 0.047 probability of a woman attending an all-women college being chosen and a 0.207 probability that she abstain from alcohol. So:

P_{1} = 0.047*0.207 = 0.009729

P_{2} is the probability of a woman attending a coeducational college being chosen and abstaining from alcohol. There is a 0.953 probability of a woman attending a coeducational college being chosen and a 0.06 probability that she abstain from alcohol. So:

P_{2} = 0.953*0.06 = 0.05718

So, the probability of a randomly selected female student abstaining from alcohol is:

P = P_{1} + P_{2} = 0.009729 + 0.05718 = 0.0669

There is a 6.69% probability that a randomly selected female student abstains from alcohol.

(b) If a randomly selected female student abstains from alcohol, what is the probability she attends a coedücational colege?

<em>This can be formulated as the following problem:</em>

<em>What is the probability of B happening, knowing that A has happened.</em>

Here:

<em>What is the probability of a woman attending a coeducational college, knowing that she abstains from alcohol.</em>

It can be calculated by the following formula:

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

We have the following probabilities:

P(B) is the probability of a woman from a coeducational college being chosen. So P(B) = 0.953

P(A/B) is the probability of a woman abstaining from alcohol, given that she attends a coeducational college. So P(A/B) = 0.06

P(A) is the probability of a woman abstaining from alcohol. From a), P(A) = 0.0669

So, the probability that a randomly selected female student attends a coeducational college, given that she abstains from alcohol is:

P = \frac{P(B).P(A/B)}{P(A)} = \frac{(0.953)*(0.06)}{(0.0669)} = 0.8287

If a randomly selected female student abstains from alcohol, there is a 82.87% probability that she attends a coeducational college.

4 0
3 years ago
A student bought 11 pencils and a pad of paper. The pencils each cost the same amount. The pad of paper cost $4.99. The student
AleksAgata [21]
No lo se wey, espero estes bien :D
3 0
3 years ago
Find the midpoint of the line segment with the given endpoints.<br> (-3,-7) and (3,0)
timurjin [86]
The formula is
you take the first x (in this case I'll make it A)
and the second x value (B)
basically (A-B)/2 is what you will use to find the X coordinate of the midpoint
The Y coordinate if solved by the same formula, just using Y's instead
Sorry for not being to clear
I hope this helps
answer:
 (0,3.5)
6 0
4 years ago
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