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3 years ago

What's the proper name of the quadrilateral below?

Mathematics

2 answers:

Alenkinab [10]3 years ago

5 0

The proper name of the quadrilateral is called Parallelograms

salantis [7]3 years ago

5 0

Ok so there are many quadrelaterals

trapezoids have to have 1 parralel side

rhombuses have to have 2 pairs of parralel sides and so on

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Mrs Alivia’s bathroom is in the shape of a rectangle with a width of 6 feet. Her kitchen is in the shape of a rectangle with a w

Vedmedyk [2.9K]

Answer:

1. The length of the bathroom is equal to its width. FALSE

2. Equation 2(x+6)=29 can be used to find the length of the bathroom, x.

TRUE

3. The legend of the bathroom is 11.5 feet. FALSE

4. The equation 2 x+6=29 can be used to find the length of bathroom, x.

FALSE

5. The length of the bathroom is 8.5 feet. TRUE

Step-by-step explanation:

Here, given:

The width of the bathroom = 6 feet

The width of the kitchen = 10.75 ft

The perimeter of the bathroom = 29 feet

Let us assume the length of the bathroom = k units

PERIMETER OF A RECTANGLE = 2 ( LENGTH + WIDTH)

Now, for the Mrs Avila's bathroom

29 feet = 2 (k + 6)

⇒ 29 = 2k + 12

or, 2 k = 29 - 12 = 17

⇒ k = 17/2 = 8.5 feet

So, the length of the bathroom = 8.5 units

Now, let us consider the given statements:

1. The length of the bathroom is equal to its width. FALSE

As here, Length= 8.5 units and width = 6 units

2. Equation 2(x+6)=29 can be used to find the length of the bathroom, x.

TRUE

3. The legend of the bathroom is 11.5 feet.

FALSE, the length of the bathroom is 8.5 units.

4. The equation 2 x+6=29 can be used to find the length of bathroom, x.

FALSE, the correct equation that can be used is 2x + 12 = 29

5. The length of the bathroom is 8.5 feet.

TRUE

5 0

3 years ago

2logx=3-2log(x+3) solve for x

AVprozaik [17]

Answer:

$\large\boxed{x=\dfrac{-3+\sqrt{40+10\sqrt{10}}}{2}}$

Step-by-step explanation:

$2\log x=3-2\log(x+3)\\\\Domain:\ x>0\ \wedge\ x+3>0\to x>-3\\\\D:x>0\\============================\\2\log x=3-2\log(x+3)\qquad\text{add}\ 2\log(x+3)\ \text{to both sides}\\\\2\log x+2\log(x+3)=3\qquad\text{divide both sides by 2}\\\\\log x+\log(x+3)=\dfrac{3}{2}\qquad\text{use}\ \log_ab+\log_ac=\log_a(bc)\\\\\log\bigg(x(x+3)\bigg)=\dfrac{3}{2}\qquad\text{use the de}\text{finition of a logarithm}\\\\x(x+3)=10^\frac{3}{2}\qquad\text{use the distributive property}$

$x^2+3x=10^{1\frac{1}{2}}\\\\x^2+3x=10^{1+\frac{1}{2}}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\x^2+3x=10\cdot10^\frac{1}{2}\qquad\text{use}\ \sqrt[n]{a}=a^\frac{1}{n}\\\\x^2+3x=10\sqrt{10}\qquad\text{subtract}\ 10\sqrt{10}\ \text{from both sides}\\\\x^2+3x-10\sqrt{10}=0\\\\\text{Use the quadratic formula}\\\\ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\a=1,\ b=3,\ c=-10\sqrt{10}\\\\b^2-4ac=3^2-4(1)(-10\sqrt{10})=9+40\sqrt{10}\\\\x=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2(1)}=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2}\\\\x=\dfrac{-3-\sqrt{10+10\sqrt{10}}}{2}\notin D$

6 0

2 years ago

The first metacarpal bone is located in the wrist. The scatterplot below shows the relationship between the length of the first

gulaghasi [49]

The question is incomplete so I am writing the complete question below and attaching the scatter plot as well.

The first metacarpal bone is located in the wrist. The scatterplot below shows the relationship between the length of the first metacarpal bone and height for 9 people. The line of best fit is also shown

How many of the nine people have an actual height that differs by more than 3 centimeters from the height predicted by the line of best fit?

Answer:

4 people have an actual height that differs by more than 3 cm from the height predicted by the line of best fit.

Step-by-step explanation:

The question is asking us to identify which people have a height that is more than 3 cm greater or more than 3 cm less then the height predicted by the line of best fit. Hence, we need to look at the outliers of the line if best fit i.e. the points which do not lie on the line. We need to select the points that differ by 3 or more cm.

So, we can see that the first person (4 cm) has an actual height of 157 cm but the line of best fit shows the height is 161.5. So, there is a difference of more than 3 cm (161.5 - 157 = 4.5).

The second outlier at 4.3 has an actual height of 175 cm but the line of best fit shows a height of 167 cm. There is a difference of 8 cm hence this person also has an actual height which differs by more than 3 cm from the line of best fit.

At 4.8 cm metacarpal bone height, the person's actual height is 172 cm but the graph shows a height of 176 cm hence this person also has an actual height which differs by more than 3 cm from the line of best fit.

At 4.9 cm on the x-axis, the person has an actual height of 183 cm but the line of best fit shows 178 cm so this person also has an actual height which differs by more than 3 cm from the line of best fit.

So, in total there are 4 people out of 9 whose heights differ by more than 3 cm from the line of best fit.

6 0

2 years ago

Math question down below

Alja [10]

Answer:

E is the only one that ends with 70 and is also all multiples of 6.

4 0

3 years ago

SI TENGO 5 L DE AGUA A 5,7O Y 500ML DE ACEITE A 1,25 ¿CUANTO VALE EL LITRO DE ACEITE Y EL LITRO DE AGUA? REDONDEA A LAS CENTESIM

LuckyWell [14K]

Answer:

use a translation

Step-by-step explanation:

sorry

7 0

2 years ago