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2 years ago

Describe in your own words what a hyperbola is.

Mathematics

1 answer:

nalin [4]2 years ago

7 0

Answer:

A conic section that can be thought of as an inside-out ellipse

Step-by-step explanation:

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1 ) Tim earns $12.50 an hour cleaning houses. If he works from 8:00am to 2:00pm,

AVprozaik [17]

Answer:

$75

Step-by-step explanation:

First, we will find how many hours he worked. 8:00-12:00 is 4 hours, and 12:00-2:00 is 2 hours, so he worked a total of 6 hours.

Next, we have to multiply the hours worked by his hourly wage.

12.50*6=75

8 0

2 years ago

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What is 19.6 divided by 7

Lemur [1.5K]

19 divided by 7 = 2.8

7 0

3 years ago

Last one for this :)

ddd [48]

Answer:

2/21 :)

Step-by-step explanation:

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2 years ago

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Correct answer gets Brainliest! Solve for x.

Simora [160]

Subtract 13 from both sides:

$-7-13 \geq -5x$

$-20 \geq -5x$

Divide both sides by -5. Since this is a negative number, you have to invert the inequality sign:

$4 \leq x$

Which means

$x \geq 4$

4 0

2 years ago

Read 2 more answers

F(x)

mina [271]

a) Since both limits are distinct and do not exist, we conclude that x = - 1 is not part of the domain of the rational function.

b) The function $f(x) = \frac{x}{x^{2}+ x}$ is equivalent to the function $g(x) = \frac{1}{x + 1}$ .

<h3>How to determine whether a limit exists or not</h3>

According to theory of limits, a function f(x) exists for x = a if and only if $\lim_{x\to a^{-}} f(x) = \lim_{x \to a^{+}} f(x)$ . This criterion is commonly used to prove continuity of functions.

Rational functions are not continuous for all value of x, as there are x-values that make denominator equal to 0. Based on the figure given below, we have the following lateral limits:

$\lim_{x \to -1^{-}} \frac{x}{x^{2}+x} = - \infty$

$\lim_{x \to -1^{+}} \frac{x}{x^{2}+x} = + \infty$

Since both limits are distinct and do not exist, we conclude that x = - 1 is not part of the domain of the rational function.

In addition, we can simplify the function by algebra properties:

$\frac{x}{x^{2}+ x} = \frac{x}{x\cdot (x + 1)} = \frac{1}{x + 1}$

$g(x) = \frac{1}{x + 1}$

The function $f(x) = \frac{x}{x^{2}+ x}$ is equivalent to the function $g(x) = \frac{1}{x + 1}$ .

To learn more on lateral limits: brainly.com/question/21783151

#SPJ1

7 0

1 year ago