The answer to this question is false.
Answer:
–625 J
Explanation:
So, we got this formula for the work
W=mgd(Cosθ)
but remember when it's liftin somethin, its work gon be against the work of gravity, so
Cos180°= –1
W=500×1.25×(–1)
W= –625 J
Explanation:
(a) We know that the acceleration of the car is given by :
a = change in speed / time taken
If the speed of the car is constant in a straight line, the acceleration of the car is zero because there is no change in the speed of the car.
(b) For the driver steer a car traveling at constant speed so that the magnitude of the acceleration remains constant, the driver should drive the car in the circular path. This is because, in circular path the speed of an object remains the same while its velocity changes.
<span>TRUE
The force that opposes the movement of an object through water is called drag. This is a type of frictional force. This force normally depends on the density and the viscosity of the fluid in question. The liquid which has more density and more viscosity or stickiness will produce a greater amount of drag force on an object than a fluid that is less dense and less viscous in nature. River water normally has less drag than that of sea water. </span><span> <span>
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