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kirill [66]
4 years ago
12

A train leaves the train station at noon and travels at a constant speed of vt = 50 mi/hr on a straight track. 2 hr later, a car

leaves the same train station and travels in the same direction at vc = 70 mi/hr on a road next to the train track. How far from the station is the place where the car catches up with the train? x =
Physics
1 answer:
asambeis [7]4 years ago
6 0

Answer:

350 miles

Explanation:

When the car starts 2 hours later, the train would have a head start of

50 * 2 = 100 miles

The speed of the car relative to the train is

70 - 50 = 20 mi/hr

For the car to catch up with the train, it must cover the 100 miles difference at the rate of 20mi/hr. So the time it would need to cover this difference is

100 / 20 = 5 hours

After 5 hours, the car would have traveled a distance of

5 * 70 = 350 miles which is also the distance from the station to where the car catches up

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A family car has a mass of 1400 kg. In an accident it hits a wall and goes from a speed of 27 m/s to a standstill in 1. 5 second
madreJ [45]

The force involved is = 25200 Newton

Given the values in the questions,

Mass = 1400 kg

Speed or velocity of the car = 27 m/s

Time is given = 1.5 seconds

According to the formula of force,

⇒ Force = Mass x Acceleration

⇒ Force = 1400 x Acceleration ----- equation 1

Now to calculate the value of acceleration we will use,

⇒ Acceleration = (Velocity or Speed) / Time

⇒ Acceleration = 27 / 1.5

⇒ Acceleration = 18 m/s^{2}

Putting the value of acceleration in equation 1,

⇒ Force = 1400 x 18

⇒ Force = 25200 Newton

Therefore, the force involved is = 25200 Newton

To learn more about Force,

brainly.com/question/13191643

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8 0
1 year ago
A neutral solid metal sphere of radius 0.1 m is at the origin, polarized by a point charge of 2 × 10−8 C at location m. At locat
liraira [26]

Answer: E = 1.8 *10 ^{4} N

Explanation: The formulae for intensity of an electric field of a solid metal sphere relative to a point is given below

E =\frac{Kq}{r^{2} } r

where  k=9* 10^{9}N/m^{2}, q=2 *10 ^{-8} c , r = 0.1m r = is the position vector of the charge.

it has been stated in the question that the charge is placed at the center thus it has no position vector.

E=\frac{9 * 10^{9}* 2* 10^{-8}  }{0.1^{2} }\\ =\frac{18* 10^{1} }{0.01} \\=\frac{18* 10^{1} }{1 *10^{-2} } = 1.8*10^{4} N

6 0
3 years ago
Which symbol represents a type of electromagnetic radiation released during radioactive decay?
Lena [83]
The correct option is (D) Gamma ( _0^0\gamma )

Explanation:
Now this question is a tricky one because all of these options are somehow involved in radioactive decay; however, in this case the SYMBOL is required NOT the elements. There are three symbols involved in radioactive decay, which are:
1. α for alpha decay
2. β for beta decay
3. γ for gamma decay 

In the options only one symbol is present which is gamma. Hence option (D) Gamma ( _0^0\gamma ) is the correct answer.

-i
4 0
3 years ago
A 20 N south magnetic force pushes a charged particle traveling with a velocity of 4 m/s west through a 5 T magnetic field point
PtichkaEL [24]

Answer:

<u>Charge</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>particle</u><u> </u><u>is</u><u> </u><u>1</u><u> </u><u>coulomb</u><u>.</u>

Explanation:

Force, F:

{ \bf{F=BeV}}

F is magnetic force.

B is the magnetic flux density.

e is the charge of the particle.

V is the velocity

{ \sf{20 = (5 \times e \times 4)}} \\ { \sf{20e = 20}} \\ { \sf{e = 1 \: coulomb}}

8 0
3 years ago
If water is at 50* C and energy is removed from the water until it is at - 10* C
aliya0001 [1]

Answer: B) Solid water to liquid water.

Explanation: This would be the melting of water or a transition of solid water to liquid water as energy is added.

3 0
3 years ago
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