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Mrrafil [7]
3 years ago
15

Considering that microwave ovens radiate at 2.45 GHz, how would you respond to the debate

Physics
1 answer:
vlada-n [284]3 years ago
4 0
On the off chance that a 2.45 GHz microwave flag is by one means or another radiating from your microwave oven, that is exceptionally perilous and you ought to have it settled or supplanted promptly. A 1000 Watt microwave oven radiating energy into the nearby environment can, contingent upon conditions, make you lose awareness in around 12 to 15 minutes of presentation at a separation of around 10 feet.
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Squids and octopuses propel themselves by expelling water. They do this by keeping water in a cavity and then suddenly contracti
Zigmanuir [339]

Answer:

10.1 m/s

Explanation:

By Newton's third law, the force on the squid and that due to the water expelled form an action reaction pair.

And by the law of conservation of momentum,

initial momentum of squid + expelled water = final momentum of squid + expelled water.

Now, the initial momentum of the system is zero.

So, 0 = final momentum of squid + expelled water

0 = MV + mv where M = mass of squid = 6.50kg, V = velocity of squid = 2.40m/s, m =mass of water in cavity = 1.55 kg and v = velocity of water expelled

So, MV + mv = 0

MV = -mv

v = -MV/m

= -6.50 kg × 2.40 m/s ÷ 1.55 kg

= -15.6 kgm/s ÷ 1.55 kg

= -10.1 m/s

So, speed must it expel this water to instantaneously achieve a speed of 2.40 m/s to escape the predator is 10.1 m/s

4 0
3 years ago
Use the motion map to answer the question.
Lana71 [14]

Answer:

The object starts away from the origin and then moves toward the origin at a constant velocity. Next, it stops for one second. Finally, it moves away from the origin at a greater constant velocity.

3 0
3 years ago
On average, both arms and hands together account for 13% of a person's mass, while the head is 7.0% and the trunk and legs accou
BabaBlast [244]

Answer:

<em>176.38 rpm</em>

<em></em>

Explanation:

mass percentage of arms and legs = 13%

mass percentage of legs and trunk = 80%

mass percentage of head = 7%

Total mass of the skater = 74.0 kg

length of arms = 70 cm = 0.7 m

height of skater = 1.8 m

diameter of trunk = 35 cm = 0.35 m

Initial angular momentum = 68 rpm

<em>We assume:</em>

  1. <em>The spinning skater with her arms outstretched as a vertical cylinder (head, trunk, and legs) with two solid uniform rods (arms and hands) extended horizontally.</em>
  2. <em>friction between the skater and the ice is negligible.</em>

We split her body into two systems, the spinning hands as spinning rods

1. Each rod has moment of inertia = \frac{1}{3} mL^{2}

mass m of the arms is 13% of 74 kg = 0.13 x 74 = 9.62 kg

mass of each side will be assumed to be 9.62/2 = 4.81 kg

L = length of each arm

therefore,

I =  \frac{1}{3} x 4.81 x 0.7^{2} = 0.79 kg-m   for each arm

2. Her body as a cylinder has moment of inertia =  \frac{1}{2} mr^{2}

r = radius of her body = diameter/2 = 0.35/2 = 0.175 m

mass of body trunk = (80% + 7%) of 74 kg = 0.87 x 74 = 64.38 kg

I = \frac{1}{2} x 64.38 x 0.175^{2} = 0.99 kg-m

We consider each case

case 1: Body spinning with arm outstretched

<em>Total moment of inertia = sum of moments of inertia of both arms and moment of inertia of body trunk</em>

I = (0.79 x 2) +  0.99 = 2.57 kg-m

angular momentum = Iω

where ω = angular speed = 68.0 rpm = \frac{2\pi }{60} x 68 = 7.12 rad/s

angular momentum = 2.57 x 7.12 = 18.29 kg-rad/m-s

case 2: Arms pulled down parallel to trunk

<em>The momentum of inertia will be due to her body trunk alone</em> which is 0.91 kg-m

angular momentum =  Iω

=  0.99 x ω = 0.91ω

<em>according to conservation of angular momentum, both angular momentum must be equal</em>, therefore,

18.29 = 0.99ω

ω = 18.29/0.99 = 18.47 rad/s

18.47 ÷ \frac{2\pi }{60}  = <em>176.38 rpm</em>

7 0
3 years ago
Gases are ____ in cooler solvents.
Bumek [7]
Gases are more soluble in cooler solvents.
Hope this helps!
4 0
4 years ago
Need help ASAP please
Mariulka [41]

Answer:

150 N ON A P E X

Explanation:

3 0
3 years ago
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