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Mrrafil [7]
3 years ago
15

Considering that microwave ovens radiate at 2.45 GHz, how would you respond to the debate

Physics
1 answer:
vlada-n [284]3 years ago
4 0
On the off chance that a 2.45 GHz microwave flag is by one means or another radiating from your microwave oven, that is exceptionally perilous and you ought to have it settled or supplanted promptly. A 1000 Watt microwave oven radiating energy into the nearby environment can, contingent upon conditions, make you lose awareness in around 12 to 15 minutes of presentation at a separation of around 10 feet.
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Please someone answer this
blondinia [14]

Answer:

you just have to draw a line from the eye reflecting from the mirror to the object shown.

Explanation:

Dont come at me if its wrong. I think thats what their asking of you.

8 0
3 years ago
Describe what will happen to
Ostrovityanka [42]
It will be hotter and more like than 20celium degrees
4 0
3 years ago
An athlete runs at a constant velocity of 5.2 m/s. What is the velocity of the athlete relative to the ground?
dimulka [17.4K]

The relative velocity of the athlete relative to the ground is 5.2 m/s

The given parameters;

constant velocity of the athlete, V = 5.2 m/s

let the velocity of the ground = Vg = 0

The relative velocity concept helps us to determine the velocity of a moving object relative to a stationary observer.

The athlete is the moving object in this question while the ground is stationary.

The relative velocity of the athlete relative to the ground is calculated as follows;

V/V_g = V - V_g  = 5.2 - 0 = 5.2  \ m/s

Thus, the relative velocity of the athlete relative to the ground is 5.2 m/s

Learn more here: brainly.com/question/24430414

5 0
3 years ago
Suppose you increase your walking speed from 6 m/s to 15m/s in a period of 3 seconds what is your acceleration
choli [55]
Avg acceleration; under constant acceleration condition only; = Vf-Vi/time
a=Vf-Vi/time=(15m/s-6m/s)/(3s)=
(9m/s)/(3s)=3m/s^2

Hope this helps. Thanks.
7 0
3 years ago
The period T of a pendulum of length L is measured to determine g at the surface of Earth. The equation used is T=2π√L/g. The ma
saul85 [17]

Answer:

C: Variation in the value of g as the pendulum bob moves along its arc.

Explanation:

The formula for period of a simple pendulum is given by;

T = 2π√(L/g)

Where;

L is length

g is acceleration due to gravity

Now, from this period equation, it is clear that the only thing that can affect the period of a simple pendulum are changes to its length and acceleration due to gravity.

Looking at the options, the only one that talks about either the length or gravity as being potential causes of the error is option C

4 0
3 years ago
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