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Anna11 [10]
3 years ago
10

Solve : 2/3+(x)=3 A)-4/3 B)-7/3 C)4/3 D)7/3

Mathematics
2 answers:
serious [3.7K]3 years ago
8 0

Answer:

D

Step-by-step explanation:

2/3+x=3

Step 1: Subtract 2/3 from both sides.

x+ 2 /3 − (2/3 )=3−(2/3)

You'll end up with 7/3 :D

have a great day! :D))

snow_tiger [21]3 years ago
4 0

Answer:

a

Step-by-step explanation:

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3 years ago
In ΔJKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of ∠K, to the nearest 10th of a degree.
Tasya [4]

Given:

In ΔJKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°.

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The value of  ∠K to the nearest 10th of a degree.

Solution:

According to the Law of Sine:

\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}

We have, In ΔJKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°.

Using the Law of Sine, we get

\dfrac{j}{\sin J}=\dfrac{k}{\sin K}

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3.8\sin K=4.1\sin (63^\circ)

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