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3 years ago

Solve : 2/3+(x)=3 A)-4/3 B)-7/3 C)4/3 D)7/3

Mathematics

2 answers:

serious [3.7K]3 years ago

8 0

Answer:

Step-by-step explanation:

2/3+x=3

Step 1: Subtract 2/3 from both sides.

x+ 2 /3 − (2/3 )=3−(2/3)

You'll end up with 7/3 :D

have a great day! :D))

snow_tiger [21]3 years ago

4 0

Answer:

Step-by-step explanation:

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Joel wants to buy a new tablet computer from a store having a 20% off sale on all tablets. The tablet he wants has an original c

earnstyle [38]

Answer:

<u>Joel will have to pay $ 159.60 for the tablet.</u>

Step-by-step explanation:

1. Information given to us to answer the question correctly:

Discount percentage of the tablets = 20%

Original cost of the tablet = $ 190

Sales tax = 5%

2. How much will Joel pay for the tablet? Show your work in your notebook. Remember to use $.

Let's find the discounted price and the sales tax for that price, this way:

Discounted price = Original price - Discount

Discounted price = 190 - (190 * 0.2)

Discounted price = 190 - 38 = 152

Sales tax of the discounted price = 152 * 0.05

Sales tax = 7.60

Joel will have to pay = Discounted price + Sales tax

Joel will have to pay = 152 + 7.60

5 0

3 years ago

At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?

hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

$d*sin(\theta) = m\lambda$

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle

At the first-order maximum (m=1) at 20.0 degrees we have:

$\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342$

Now, to produce a second-order maximum (m=2) the angle must be:

$sin(\theta) = \frac{\lambda}{d}*m$

$\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}$

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.

I hope it helps you!

6 0

3 years ago

Find a such that the solution of y'' + y' − 2y = 0, y(0) = a, y' (0) = 1 tends to zero as t → +∞.

Kay [80]

Answer:

Step-by-step explanation:

$y'' + y' − 2y = 0, y(0) = a, y' (0) = 1$

Auxialary equation is

$m^2+m-2=0\\m=-2,1$

General solution is

$y=Ae^{-2x} +Be^x$

$y(0) = A+B =a$

$y'(0) = -2Ae^{2x} +Be^x = -2A+B = 1$

Eliminate B to get

3A =a-1

We know that y tends to 0 when x tends to infinity for any finite A

i.e. a should be a finite real number.

8 0

3 years ago

If the two angles are complementary, find the measure of each of angle. I am having trouble decoding this problem in it it says

telo118 [61]

Answer:

f=10

Step-by-step explanation:

I don't know a formula for this but I can see that <CRE is a 90° angle so 7f+2f=90 and if f=10 7f=70 and 2f=20 which fits

3 0

3 years ago

20 points!!!!

valentinak56 [21]

No, because the sample was not random

8 0

3 years ago

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