All categories

3 years ago

69/14 as a mixed number

Mathematics

2 answers:

Otrada [13]3 years ago

4 0

Answer:

6914 is 4 with a remainder of 13

Step-by-step explanation:

azamat3 years ago

3 0

Answer:

4 13/14

Step-by-step explanation:

simplify the equation

You might be interested in

State the line of reflection. A B 2 C D'o Chri А" B Reflection across (type with no spaces) Espacio en Blanco 1:

zubka84 [21]

Answer:

y = 0

Step-by-step explanation:

The image is reflected across the y-axis

3 0

2 years ago

Which triangles are congruent? How do you know?

choli [55]

Use the side lengths! C and D have lengths of 3 and heights of 4.
Also use how far away they are from the axis.

Both C and D are 2 away from each axis on the end point.
This also goes with A.
However, B does not seem to be congruent in the sense of (coordinates)
It is the same length and height.

3 0

3 years ago

Read 2 more answers

Write a expression that represents 72 divided by n plus 4

jeka57 [31]

Answer:

72 divided by n + 4

Step-by-step explanation:

its actually directly in the picture

5 0

3 years ago

Find the 2nd Derivative:<br> f(x) = 3x⁴ + 2x² - 8x + 4

ad-work [718]

Answer:

$f''(x)=36x^2+4$

Step-by-step explanation:

Let's start by finding the first derivative of $f(x)= 3x^4+2x^2-8x+4$ . We can do so by using the power rule for derivatives.

The power rule states that:

$\frac{d}{dx} (x^n) = n \times x^n^-^1$

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

Let's apply the power rule to the function f(x).

$\frac{d}{dx} (3x^4+2x^2-8x+4)$

Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)$

Simplify the equation.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)$
$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8(1)+0)$

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8)$
$f'(x)=12x^3+4x-8$

Now, this is only the first derivative of the function f(x). Let's find the second derivative by applying the power rule once again, but this time to the first derivative, f'(x).