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3 years ago

6 pounds 14 ounces = ounces

Mathematics

1 answer:

abruzzese [7]3 years ago

7 0

Answer:

110 oz

Step-by-step explanation:

6 lbs = 96 oz

96 oz + 14 oz = 110 oz

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WILL MARK BRAINLIEST!! Which of the following ordered pairs are y-intercepts? Check all that apply.

Y_Kistochka [10]

Y intercept is where the line meets the Y axis
So the points shd be in (0,y) form.

So (0,0) (0,-7) (0,-0.25) are the y-intercepts in the following.

8 0

3 years ago

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The measure of a vertex angle of an isosceles triangle is 120° and the length of a leg is 8 cm. Find the length of a diameter of

Goryan [66]

ANSWER

The length of a Diameter is 3.714

EXPLANATION

The circumscribed triangle is shown in the attachment.

We use the cosine ratio to find the altitude of the isosceles triangle.

$\cos(60 \degree) = \frac{altitude}{hypotenuse}$

$\cos(60 \degree) = \frac{altitude}{8}$

Altitude =8cos(60°)

Altitude=4cm

Let the upper half of the altitude be y cm.

Then the radius of the circle is (y-4)cm

The upper radius meets the tangent at right angles.

From the smaller right triangle,

$\sin(60 \degree) = \frac{4 - y}{y}$

$y\sin(60 \degree) = 4 - y$

$y\sin(60 \degree) + y= 4$

$(\sin(60 \degree) + 1)y= 4$

$y= \frac{4}{\sin(60 \degree) + 1}$

$y = 16 - 8 \sqrt{3}$

y=1.857

The diameter is 2y

$d = 32 - 16 \sqrt{3}$

=2(1.875)

The length of a Diameter is 3.714

7 0

3 years ago

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The side of rhombus is 14 in. The obtuse angle is 160º. Find the longer diagonal of the rhombus.

Mandarinka [93]

Answer:

x = 27.57 in to the nearest hundredth.

Step-by-step explanation:

The longer diagonal is opposite the obtuse angle.

Also as it is a rhombus all sides = 14 in.

Use the Cosine Rule:

x^2 = 14^2 + 14^2 - 2*14^2 cos 160

x^2 = 760.36

x = sqrt 760.36

x = 27.57 in.

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3 years ago

Solve the equation on the interval [0,2π). cos^4x=cos^4xcscx

Alisiya [41]

$\bf cos^4(x)=cos^4(x)csc(x)\\\\
-----------------------------\\\\
cos^4(x)=cos^4(x)\cfrac{1}{sin(x)}\implies cos^4(x)=\cfrac{cos^4(x)}{sin(x)}
\\\\\\
cos^4(x)sin(x)=cos^4(x)\implies cos^4(x)sin(x)-cos^4(x)=0
\\\\\\
cos^4(x)[sin(x)-1]=0\to 
\begin{cases}
cos^4(x)=0\to x=cos^{-1}(0)\\
----------\\
sin(x)-1=0\\
sin(x)=1\to x=sin^{-1}(1)
\end{cases}$

$\bf \measuredangle x = cos^{-1}(0)\implies \measuredangle x = 
\begin{cases}
\frac{\pi }{2}\\\\
\frac{3\pi }{2}
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3 years ago

Consider the reflection of parallelogram PQRS across the line of reflection wy

solniwko [45]

Answer:

Consider the reflection of the parallelogram PQRS across the line of reflection wy if RR = 14 Then RZ= If SX=5 then = 5

Step-by-step explanation:

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3 years ago