Part A
The given line passes through (-2,2) and it is parallel to the line

We need to determine the slope of this line by writing it in slope -intercept form.


The slope of this line is

The line parallel to this line also has slope

The equation is

We substitute (-2,2)


The required equation is

PART B
The given line is

The slope of this line is

The slope of the line perpendicular to it is

The equation of the line is

We substitute the point, (-2,2)



The equation of the perpendicular line is
Perimeter = 2L + 2W
42= 2L + 2(8)
26 = 2L
13 = L
Step-by-step explanation:
Sn=n/2(2a+(n-1)d)
910=n/2{2a+(n-1)d}
1820=n{2a+(n-1)d}
1820=20{2a+(20-1)d}
1820=20{2a+19d}
91=2a+19d
An=a+(n-1)d
95=a+(20-1)d
95=a+19d
91=2a+19d
---------------
4=-a
a=-4
91=2a+19d
91=2(-4)+19d
91=-8+19d
91+8=19d
99=19d
d=99/19
A=-4
Answer:
D
Step-by-step explanation:
Remark
The first thing you must do is notice that <D = <BEA. Mark it that way on your diagram.
The Second thing you need to notice is that <BEA and <A are equal because <A and <D are marked as equal.
So both the large triangle and the small one are isosceles. because 2 of the 3 angles are equal.
Now are you ready for this? That means that BA = 10 because BA is opposite one of the 2 equal angles in the small triangle. So now you are ready to set up a proportion.
Proportion
AB / AC = AE/AD
Givens
AB = 10
AC = 18
AE = 8
AD = x + 8
Solution
Substitute the Givens into the Proportion.
10/18 = 8/(x + 8) Cross multiply
10(x + 8) = 8 * 18 Simplify both sides
10x + 80 = 144 Subtract 80 from both sides
10x + 80 - 80 = 144 - 80
10x = 64 Divide by 10
10x/10 = 64/10
Answer: x = 6.4