Question

HELP I NEED HELP ASAP

Answer 1

9514 1404 393

Answer:

  C.  (10, 5), (5, 0), (0, 5)

Step-by-step explanation:

In order for the square to have an area of 50 square units, its side lengths must be √50 = 5√2 units long. The only way to get such a length with integer coordinates is for the sides of the square to be themselves the diagonals of a square 5 units on a side.

That is, two of the other vertices of the square must be among ...

  (5±5, 10±5) ⇒ (10, 15), (0, 15), (10, 5), (0, 5)

Only choice C contains two of the vertices on this list.