PLZ HELP Due in an hour!

Mathematics

1 answer:

frosja888 [35]2 years ago

6 0

Answer:

1. No, 2. 46, 3. The amount of tails flips would be more than the amount of heads flips.

Step-by-step explanation:

1 is no because .77 and .23 are not equal to .5, so her prediction was wrong. 2 is 46 because if you double both the numbers (to get a total of 200 flips), you would get 154 tails and 46 heads. 3 is more tails than heads because that is what we have observed.

You might be interested in

-3x+4y=-4 -2x+5y=9<br>solve the following system of equations

Vesnalui [34]

the answer is x= 8, and y=5

3 0

2 years ago

Read 2 more answers

Which operation properly transforms matrix I to matrix II?

Y_Kistochka [10]

Answer:

Step-by-step explanation:

Replace R1 with 1 and R3 with 0 you have -2(1)+0 which equals 0 and that matches matrix II. Repeat the process with the other numbers in R1 and R3 and they all come out equal therefor the answer is D.

8 0

2 years ago

Find the output value of the function. f(x)=5x-8 for f(7)

Molodets [167]

Answer:

Step-by-step explanation:

f(x) = 5x - 8

f(7) = 5(7) - 8 = 27

3 0

3 years ago

Read 2 more answers

What fraction of a dollar would this represent in lowest terms

Elza [17]

I think 1/4 is the answer

3 0

3 years ago

Read 2 more answers

Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for each function.

Lunna [17]

Answer:

The first three nonzero terms in the Maclaurin series is

$\mathbf{ 5e^{-x^2} cos (4x) }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }$

Step-by-step explanation:

GIven that:

$f(x) = 5e^{-x^2} cos (4x)$

The Maclaurin series of cos x can be expressed as :

$\mathtt{cos \ x = \sum \limits ^{\infty}_{n =0} (-1)^n \dfrac{x^{2n}}{2!} = 1 - \dfrac{x^2}{2!}+\dfrac{x^4}{4!}-\dfrac{x^6}{6!}+... \ \ \ (1)}$

$\mathtt{e^{-2^x} = \sum \limits^{\infty}_{n=0} \ \dfrac{(-x^2)^n}{n!} = \sum \limits ^{\infty}_{n=0} (-1)^n \ \dfrac{x^{2n} }{x!} = 1 -x^2+ \dfrac{x^4}{2!} -\dfrac{x^6}{3!}+... \ \ \ (2)}$