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3 years ago

5

Manny collected data on the number of quarters that 13 of his classmates have. Draw a box plot of the data and use it to find th

e interquartile range and range.

1 answer:

Irina18 [472]3 years ago

5 0

Answer:

the iqr is 3 , and the range is 7

Step-by-step explanation:

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16 The perimeter of the pentagon is equal to the perimeter of the square.

STatiana [176]

7x+2

Step-by-step explanation:

add all the sides of the pentagon and make it equal to the perimeter of the square which is 4y

sides of the pentagon are

5x+3

2x+3

7x+4

9x-10

5x+8

28x+8=4y

7x+2 = y

7x+2 = answer

gathmath

gathmathier6961

another way :

in a standardized test you may want to use real numbers

make x equal a prime number like 3

so then the sides are

18

9

25

17

23

=

92

then divide by 4

23

then divide by 3

which is 7 remainder of 2

which is

7x+2

8 0

2 years ago

Please heeelp !! <br> Missing triangles !!

Airida [17]

Answer: ABC seem to be equilateral

so A=B=C=60

D=42

E=35

F=35

G=55

H=45

I=45

j=15

k=15

L=75

M=180

N=11

O=35

P=11

Q=55

R=55

S=32

T=32

U=69

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please help!! MathsWatch, Surd Expressions, Clip 207c

dexar [7]

Answer:

$A=(72+36\sqrt{3})\ mm^2$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

Let

a ----> the height of rectangle in mm

b ---> the base of rectangle in mm

step 1

Find the base of rectangle

$b=AB+BC+CD+DE$ ----> by segment addition postulate

substitute

$b=3+3+3+3=12\ mm$

step 2

Find the height of rectangle

$a=FB+CG+GH$ ---> by segment addition postulate

substitute the given values

$a=3+CG+3\\a=6+CG$

Find the length sides CG

Applying the Pythagorean Theorem

$BG^2=BC^2+CG^2$

substitute the given values

$6^2=3^2+CG^2$

$CG^2=6^2-3^2$

$CG=\sqrt{27}\ mm$

simplify

$CG=3\sqrt{3}\ mm$

therefore

$a=(6+3\sqrt{3})\ mm$

step 3

Find the area of rectangle

$A=ab$

we have

$a=(6+3\sqrt{3})\ mm$

$b=12\ mm$

substitute

$A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2$

8 0

3 years ago

Helpppppppp pleaseee

In-s [12.5K]

Answer:

Dezias' pensil is 5.11-1.09=4.02 inches long

Paul's pencil is 4.02+2.05=6.07 inches long

Miguel's pencil is 5.11+1.75=6.86 inches long

Combined are 5.11+4.02+6.07+6.86=22.06

The fraction is 22.06/12=1.8383333...

3 0

3 years ago

8 – 6 ∙ 4 + 10 ÷ 2 =

igor_vitrenko [27]

Answer:

-11

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers