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Solnce55 [7]
3 years ago
11

(2x2 + 1) + 3/2x2=1=4

Mathematics
1 answer:
guajiro [1.7K]3 years ago
4 0

Answer:

3(2×2+1)+3×(2×2)/3=1×3=4×3

36+3+4=3=12

36+3+4-3-12

43-15

28

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For the graph shown, select the statement that best represents the given system of equations.
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The answer is C.<span>consistent and independent</span>
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Help please! i appreciate it
BlackZzzverrR [31]

Answer:- 1) there are three terms

2) 3,4,1

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3 years ago
Please Help ! Will give brainliest!
sveta [45]

Answer:

D: I and IV only.

Step-by-step explanation:

We can go through each statement and examine its validity.

I) All congruent triangles are similar.

For congruent triangles, all of its corresponding sides and angles are congruent.

Since all angles are congruent, this fulfills the AA Similarity criterion. Thus, I is true.

II) All similar triangles are congruent.

Congruence guarantees similarity, but similarity does not guarantee congruence.

Two triangles need only two congruent angles to guarantee similarity, while two congruent angles does guarantee congruence. II is false.

III) All right triangles are similar.

Triangles are similar through the AA criterion. One angle of a right triangle must be 90, so this leaves 90 for the two remaining angles. Since these two angles can be anything that sum to 90, we are not guaranteed similarity. For example, 20 - 70 - 90 and 30 - 60 - 90 triangles. They are both right triangles, but are not similar. III is false.

IV) All isosceles right triangles are similar.

Again, since we have a right triangle, one angle is 90, which leaves two remaining angles that must sum to 90.

However, since it is isosceles, the two remaining angles must measure the same. Only one solution exists then: both angles must be 45.

Since all angles must be 45 - 45 - 90, it fulfills the AA Criterion. Thus, all isosceles right triangles are similar. IV is true.

The correct statements are I and IV.

3 0
3 years ago
Evaluate h(5t^{2})given that h(t)=17-11t
Gala2k [10]
h(t)=17-11t
h(5t^{2})=17-11(5t^{2})
h(5t^{2})=17-55t^{2}
5 0
4 years ago
The equation of a circle is given below. Identify the center and radius. Then graph the circle.
Blizzard [7]

Answer:

  • Center = (3, 0)
  • Radius = 3
  • Graph = see below

Concept:

Here, we need to know the idea of the circle equation.

Circle equation: (x - h)² + (y - k)² = r²

(h, k) = center

r = radius

x = variable

y = variable

Solve:

<u>Given expression </u>

(x - 3)² + y² = 9

<u>Find the point of the center</u>

(h, k) = \boxed{(3,0)}

<u>Find the length of the radius</u>

r² = 9

\boxed{r=3}

Hope this helps!! :)

Please let me know if you have any questions

3 0
3 years ago
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