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Keith_Richards [23]
3 years ago
6

Hello, someone please help me with this question.

Mathematics
1 answer:
aleksandrvk [35]3 years ago
3 0

Answer:

Ron is because the 7 and the 2 are the inside box while 10 and 12 are the outside, hope this helps :)

Step-by-step explanation:

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PLEASE HELP WITH PRE CALC
Oksanka [162]

Answer:

-3/2

Step-by-step explanation:

The average rate of change is synonymous to the slope.

So, to find the average rate of change from the interval x=-2 to x=2, first find the y-values at x=-2 and x=2.

At x=-2, we can see that y is 4. Thus, we have (-2,4).

At x=2, we can see that y is -2. Thus, we have (2,-2).

Now, use the slope formula. The formula for slope is:

m=\frac{y_2-y_1}{x_2-x_1}

Let (-2,4) be x₁ and y₁ and let (2,-2) be x₂ and y₂. Therefore:

m=\frac{-2-4}{2--2}

Simplify:

m=\frac{-6}{4}

Reduce:

m=-3/2

So, our average rate of change from the interval x=-2 to x=2 is -3/2.

5 0
3 years ago
sally walks 4 miles north and then 3 miles east. how far has she walked as the crow flies from her starting point?​
wolverine [178]

Answer:

5

Step-by-step explanation:

Use Pythagorean’s theorem

Find the hypotenuse

16 + 9 = c squared

25 = c squared

5 = c

8 0
3 years ago
What is the value of x +when x=3?​
sesenic [268]

Answer:

when x = 3, x would equal 3 since x can be substituted as 3, aka chancge any xes into 3 if they give you yhat info

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Pierce works at a tutoring center on the weekends. At the center, they have a large calculator to use for demonstration purposes
icang [17]

Answer:

504 millimeters (or 50.4 cm)

Step-by-step explanation:

   Width of key in student calculator = 14 millimeter (1.4 cm)

   Width of key in demonstration calculator = 2.8 cm

Thus, the demonstration calculator's dimensions are twice that of students' (in cm)

Also given, student calculator height as 252 millimeters (25.2 cm)

Thus demonstration calculator height will be twice of that = 50.4 cm (or 504 millimeters)

5 0
3 years ago
You recently took a statistics exam in a large class. The instructor tells the class that the scores were Normally distributed,
Lunna [17]

Answer:

b. the area to the right of 2

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X, which is also the area to the left of Z. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X, which is the area to the right of Z.

In this problem:

X = 96, \mu = 72, \sigma = 12

Z = \frac{X - \mu}{\sigma}

Z = \frac{96 - 72}{12}

Z = 2

Percentage who did better:

P(Z > 2), which is the area to the right of 2.

5 0
3 years ago
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