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shtirl [24]
3 years ago
7

26 + 58 rounded to the nearest ten​

Mathematics
2 answers:
Tanya [424]3 years ago
4 0

Answer:

80

Step-by-step explanation:

slamgirl [31]3 years ago
3 0

Answer:

80

Step-by-step explanation:

26+58=84

Rounded=80

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87 is 15% of what number​
jarptica [38.1K]

Answer:

580

Step-by-step explanation:

Let's translate this word for word.

87 is 15% of what number

87 = 15% times x

87=.15 times x

87=.15 \cdot x

Divide both sides by .15

\frac{87}{.15}=\frac{.15x}{.15}

Cancel out the common factor of .15 on the right; that is .15/.15=1.

580=x

580 is the number

8 0
3 years ago
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Please answer correctly! I will Mark you as Brainliest!
densk [106]

Answer:

Im pretty sure its 7 but wait for someone else to awnser id.k if i did my math correctly or not lol

Step-by-step explanation:

5 0
3 years ago
CAN SOMEONE PLEASE ANSWER THIS CORRECTLY QUICKLY PLEASE
kkurt [141]
All I could think is subtract and divide
6 0
2 years ago
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What is the value of x?<br><br> 3 • (–4) • x = 0<br><br> x =
dedylja [7]
Multiply out
remember thatn (-) times (+)=(-) so
+3 times -4=-12
-12x=0
the only number that will work is 0 since 0 times anything=0

x=0
5 0
2 years ago
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F divides HJ in the ratio 3:1. If H = (-11,7) and J = (5,3), what are the<br> coordinates of F?
Hatshy [7]

Answer:

The coordinates of HF are (1, 4)

Step-by-step explanation:

The parameters of the line are;

The coordinate of the end points are H = (-11, 7), and J = (5, 3)

The ratio by which the point F divides the line = 3:1

The segments in the line are HF, and FJ

Therefore;

The fraction of the length of HJ that is represented by HF = 3/(3 + 1) × HJ = 3/4 × HJ

HF = 3/4 × HJ

Which gives the coordinates of the point F as follows;

Coordinate of F = (-11 +(5 - (-11))×3/4, 7 + (3 - 7)×3/4) =  (1, 4)

The coordinates of F are (1, 4)

We check the length of HF, from the equation for the length to of a line to get;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

l_{HF} = \sqrt{\left (4-7  \right )^{2}+\left (1-(-11)  \right )^{2}} = \sqrt{\left (-3  \right )^{2}+\left (12  \right )^{2}} = 3\cdot \sqrt{17}

Similarly, we check the length of HJ, to get;

l_{HF} = \sqrt{\left (3-7  \right )^{2}+\left (5-(-11)  \right )^{2}} = \sqrt{\left (-4  \right )^{2}+\left (16  \right )^{2}} = 4\cdot \sqrt{17}

The length of HF = 3·√(17)

The length of HJ = 4·√(17)

Therefore, from HF = 3/4× HJ, we have;

HF = 3/4 × 4·√(17) = 3·√(17)

Therefore, the coordinates of HF are (1, 4)

7 0
3 years ago
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