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Scorpion4ik [409]
3 years ago
12

Solve open parentheses square root of 6 close parentheses to the 8 x power = 216x−3. (1 point)

Mathematics
1 answer:
Alchen [17]3 years ago
6 0

x = −9

x = −3

x = 0

x = 4
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Find the length of AC again
Bingel [31]

Answer:

B

Step-by-step explanation:

side Ac is the opposite of angle B, therefore use the sin ratio to find ac since the hypotenuse is also given

sin B=opposite/hypotenuse

sin 27=ac/15

ac=sin27×15

=6.81

I hope this helps

5 0
2 years ago
Read 2 more answers
Write the extreme and middle terms of 5 : 80 :: 4 :64
Stells [14]

Answer:

The extremes are 5 and 64.

The middle terms are 80 and 4.

Step-by-step explanation:

Given the proportion:

5 : 80 :: 4 :64

To find:

The extreme and middle terms of the given proportion.

Solution:

The given statement is in proportion if and only if the product of extremes i.e. the numbers at both the ends is equal to the product of middle numbers.

OR

First number \times Fourth number = Second number \times Third number

First of all, let us check the two products.

5 \times 64 = 320

And the second product:

80 \times 4 = 320

The product is same therefore, the given numbers are in proportion.

The extreme terms are the first and the fourth numbers.

i.e. The extremes are 5 and 64.

The middle terms are 80 and 4.

7 0
2 years ago
Find all solutions to the equation. 2sin theta - squareroot 3 = 0
Xelga [282]

Answer:

\theta =2mπ + π/3 for m ∈ Z.

Step-by-step explanation:

Given the equation 2sin\theta - \sqrt{3} = 0, we are to find all the values of \theta that satisfies the equation.

2sin\theta - \sqrt{3} = 0\\\\2sin\theta = \sqrt{3} \\\\sin\theta = \sqrt{3}/2 \\\\\theta = sin{-1} \sqrt{3}/2 \\\\\theta = 60^0

General solution for sin\theta is \theta = nπ + (-1)ⁿ ∝, where n ∈ Z.

If n is an even number say 2m, then \theta = (2m)π + ∝ where ∝ = 60° = π/3

Hence, the general solution to the equation will be \theta = 2mπ + π/3 for m ∈ Z.

8 0
3 years ago
The telephone at the family store rang 156 times in the morning, a bunch during lunch, and 201 times that afternoon. During the
BARSIC [14]

<em>Data</em>

• Morning: 156 times

,

• Lunch: x times

,

• Afternoon: 201 times

,

• Whole day: 562 times

<em>Procedure</em>

To know how many times did it ring at lunch, we have to build a relation, in which we know that the addition of the times in the morning, lunch, and afternoon equal the times it rang the whole day:

156+x+201=562

Then, we have to solve for <em>x </em>considering that it represents the times it rang during the lunch.

156-156+x+201-201=562-156-201x=562-156-201x=205

Answer: It rang 205 times during the afternoon.

8 0
1 year ago
Talerie has a bathtub that she needs to fill with wa-
levacccp [35]

Answer:

áedw

Step-by-step explanation:

đá

8 0
2 years ago
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