All categories

3 years ago

Josh says that -5/4 has the same quotient as 5/-4 Is this true or false? True False

Mathematics

2 answers:

stealth61 [152]3 years ago

6 0

The answer to this is true

Aliun [14]3 years ago

4 0

Trueeeeeeeeeeeeeeeeeee

You might be interested in

Chelsey puts twelve colored pieces of chocolate candy in a bag. Three pieces are green,

nydimaria [60]

Answer:

A) 3/110

B) 3/110

C) 3/110

D) The order doesn’t matter as long as you are drawing out the same three colors. The probability doesn’t change.

Step-by-step explanation:

A) 3/12x3/11x4/10=36/1320= 9/330 = 3/110

B) 3/12x4/11x3/10=36/1320= 9/330 = 3/110

C) 4/12x3/11x3/10=36/1320 = 9/330 = 3/110

D) The order doesn’t matter as long as you are drawing out the same three colors. The probability doesn’t change.

I hope this helps! Have a good day (PLZ GIVE BRAINLIEST)

8 0

3 years ago

I need help please so if you could help that would be nice. Also i will make brainliest

timurjin [86]

No it is not a function. You have to be able to write y=mx+b

5 0

3 years ago

What is the value of h(−2) when h(x)=3x+1 ?

scoray [572]

All you have to do is plug in the given number into the equation
h(x)=3x+1
h(x)=3(-2)+1
h(x)=-6+1
h(x)= -5

3 0

3 years ago

Angle 1 and angle 2 form a linear pair. if m angle 2 = 67. what is m angle 1

rusak2 [61]

a linear angle = 180 degrees

180-67 = 113

angle 1 = 113 degrees

5 0

3 years ago

For i≥1 , let Xi∼G1/2 be distributed Geometrically with parameter 1/2 . Define Yn=1n−−√∑i=1n(Xi−2) Approximate P(−1≤Yn≤2) with l

murzikaleks [220]

Answer:

The answer is "0.68".

Step-by-step explanation:

Given value:

$X_i \sim \frac{G_1}{2}$

$E(X_i)=2 \\$

$Var (X_i)= \frac{1- \frac{1}{2}}{(\frac{1}{2})^2}\\$

$= \frac{ \frac{2-1}{2}}{\frac{1}{4}}\\\\= \frac{ \frac{1}{2}}{\frac{1}{4}}\\\\= \frac{1}{2} \times \frac{4}{1}\\\\= \frac{4}{2}\\\\=2$

Now we calculate the $\bar X \sim N(2, \sqrt{\frac{2}{n}})\\$

$\to \frac{\bar X - 2}{\sqrt{\frac{2}{n}}} \sim N(0, 1)\\$

$\to \sum^n_{i=1} \frac{X_i - 2}{n} \times\sqrt{\frac{n}{2}}} \sim N(0, 1)\\\\\to \sum^n_{i=1} \frac{X_i - 2}{\sqrt{2n}} \sim N(0, 1)\\$

$\to Z_n = \frac{1}{\sqrt{n}} \sum^n_{i=1} (X_i -2) \sim N(0, 2)\\$

$\to P(-1 \leq X_n \leq 2) = P(Z_n \leq Z) -P(Z_n \leq -1) \\\\$

$= 0.92 -0.24\\\\= 0.68$

6 0

3 years ago