(-2)(-24)
(-3)(-16)
(-4)(-12)
(-6)(-8)
-(-1)(-48)
1*48
2*24
3*16
4*12
6*8
Answer:
The sum of all the exterior angles in a polygon is equal to 360 degrees.
Hope this helps you. Do mark me as brainliest.
Slope-intercept form is y = mx + b, where m is the slope of the line and b is the y-intercept.
For the equation y = 5x - 6, m = 5, meaning that the slope of the line is 5.
(0,3.75)(15,0)
slope(m) = (0 - 3.75) / (15 - 0) = -3.75/15 = - 0.25 or -1/4
y = mx + b
slope(m) = -1/4
(15,0)...x = 15 and y = 0
now we sub
0 = -1/4(15) + b
0 = -15/4 + b
15/4 = b
y = -1/4x + 15/4
1/4x + y = 15/4....multiply by 4
x + 4y = 15.....and since it is a solid line, it contains an equal sign...and since it is shaded above the line, it is greater.
so ur inequality is : x + 4y > = 15 (thats greater then or equal)
<h3>Given</h3>
1) Trapezoid BEAR with bases 11.5 and 6.5 and height 8.5, all in cm.
2) Regular pentagon PENTA with side lengths 9 m
<h3>Find</h3>
The area of each figure, rounded to the nearest integer
<h3>Solution</h3>
1) The area of a trapezoid is given by
... A = (1/2)(b1 +b2)h
... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77
The area of BEAR is about 77 cm².
2) The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...
... A = (1/2)ap
... A = (1/2)(s/(2tan(180°/n)))(ns)
... A = (n/4)s²/tan(180°/n)
We have a polygon with s=9 and n=5, so its area is
... A = (5/4)·9²/tan(36°) ≈ 139.36
The area of PENTA is about 139 m².
