The sides of a rhombus are equal length, so you have
... 5x + 20 = 6x + 10
... 10 = x . . . . . . . . subtract 5x+10
Then the side lengths are
... 5·10 +10 = 70
T(4,-1) means move 4 units to the right and 1 unit down.
Based on the image, M(-3,4) ; N(-2,1) ; P(-4,2)
So,
M:
-3 move 4 units to the right becomes 1
4 move 1 unit down becomes 3
M'(1,3)
N
-2 move 4 units to the right becomes 2
1 move 1 unit down becomes 0
N"(2,0)
P
-4 move 4 units to the right becomes 0
2 move 1 unit down becomes 1
P''(0,1)
I think the answer Is D fame
Wait what?? If you are talking about how much it could have caught it's 0 I guess
Answer:
a) 99.97%
b) 65%
Step-by-step explanation:
• 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.
• 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.
• 99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.
Mean of 98.35°F and a standard deviation of 0.64°F.
a. What is the approximate percentage of healthy adults with body temperatures within 3 standard deviations of the mean, or between 96.43°F and 100.27°F?
μ - 3σ
98.35 - 3(0.64)
= 96.43°F
μ + 3σ.
98.35 + 3(0.64)
= 100.27°F
The approximate percentage of healthy adults with body temperatures is 99.97%
b. What is the approximate percentage of healthy adults with body temperatures between 97 .71°F and 98.99°F?
within 1 standard deviation from the mean - that means between μ - σ and μ + σ.
μ - σ
98.35 - (0.64)
= 97.71°F
μ + σ.
98.35 + (0.64)
= 98.99°F
Therefore, the approximate percentage of healthy adults with body temperatures between 97.71°F and 98.99°F is 65%
