Jack paid $ 23000 for the ring.
<u>Solution:</u>
Given that, Jack Matthew bought a new diamond ring for $20,000
Sales tax is 5% with a 10% excise tax
<em><u>To find: total price including taxes</u></em>
Given that sales tax is 5% of 20,000
Also given that excise tax is 10%
<em>Total price = cost price + sales tax + excise tax</em>
Total price = 20,000 + 1000 + 2000
Total price = 23000
Hence, jack paid $ 23000 for the ring.
Answer:
1. 21
2. -22
3. -19
4. -17
5. -5
6. 11
7. 7
8. -9
9. -6
10. -20
11. -1
12. 20
13. -21
Step-by-step explanation:
<span>During the distribution of bonbons to her grandchildren, Grandma Claudia realized that if she distributed 11
chocolates for each of them, 10 candies would remain. In the meantime, distribute 13 chocolates
each of his grandchildren, would lack 6.
Based on this information, it is CORRECT to state that the difference between the number of candies
and the number of grandchildren is
A) 90.
B) 30.
C) -90.
D) -30.
Let n=number of candies,
and c=number of grandchildren
The story expressed in modulo gives the two following equations:
then
mod(n,11)=10 (ten left if each given 11).............(1)
mod(n,13)=-6, or
mod(n,13)=7 (7 left if each given 13)
By enumerating (1), we have
10,21,32,43,54,65,76,87,98,109...
=> 8*11+10=98
By enumerating (2), we have
7,20,33,46,59,72,85,98,101...
=> 8*13-6=98
Hence there are 8 grandchildren and 98 candies.
The difference of the number of candies and the number of grandchildren is therefore 98-8=90.
Another way to get the number of grandchildren is
c=(10-(-6))/(13-11)=8
</span>
<h2><u>
Answer with explanation</u>
:</h2>
Let 
be the distance traveled by deluxe tire .
As per given , we have
Null hypothesis : 
Alternative hypothesis : 
Since 
is left-tailed and population standard deviation is known, thus we should perform left-tailed z-test.
Test statistic : 
where, n= sample size
= sample mean
= Population mean
=sample standard deviation
For 
, we have
By using z-value table,
P-value for left tailed test : P(z≤-2.23)=1-P(z<2.23) [∵P(Z≤-z)=1-P(Z≤z)]
=1-0.9871=0.0129
Decision : Since p value (0.0129) < significance level (0.05), so we reject the null hypothesis .
[We reject the null hypothesis when p-value is less than the significance level .]
Conclusion : We do not have enough evidence at 0.05 significance level to support the claim that t its deluxe tire averages at least 50,000 miles before it needs to be replaced.
***(2x²+6x-8):(x+5)=2x-4
-2x²-10x
⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
-4x-8
4x+20
⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
12 ⇒ A. statement is true.
***When x=-5⇒2*(-5)²+6*(-5)-8=12⇒B. statement is true.
***2x²+6x-8 can also be written as (x+5)*(2x-4)+12 so (x+5) is a factor of 2x²+6x-8⇒C. statement is true.
***When x=5⇒2*5²+6*5-8=72 is not 12⇒D. statement is not true
***(2x²+6x-8):(x+5)=2x+16
-2x²+10x
⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
16x-8
-16x+80
⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
72⇒F. statement is not true
***E. statement is not true.
