Answer:

Step-by-step explanation:
Given,
Length of a rectangle = 20 inches
Perimeter of a rectangle = 64 inches
Area of a rectangle = ?
Let width of a rectangle be ' w ' .
<u>Fi</u><u>rst</u><u>,</u><u> </u><u>finding </u><u>the</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangle</u>

plug the values
⇒
Distribute 2 through the parentheses
⇒
Swap the sides of the equation
⇒
Move 2w to right hand side and change it's sign
⇒
Subtract 40 from 64
⇒
Divide both sides of the equation by 2
⇒
Calculate
⇒
Width of a rectangle ( w ) = 12 inches
<u>Now</u><u>,</u><u> </u><u>finding</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of </u><u>a</u><u> </u><u>rectangle</u><u> </u><u>having</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>2</u><u>0</u><u> </u><u>inches</u><u> </u><u>and </u><u>width </u><u>of</u><u> </u><u>1</u><u>2</u><u> </u><u>inches</u>

plug the values
⇒
Multiply the numbers : 20 and 12
⇒
Hence, Area of a rectangle = 240 inches²
Hope I helped !
Best regards!
All my work is shown in the image.
Step-by-step explanation:
Total Surface area of a pyramid is given as
= Lateral surface area + area of base.
Lateral surface area = 1/2×perimeter of base×slant height
given the base is square with side 9 in , and slant height of 12 inches.
therefore, LSA = 1/2(9*4)×12 = 216 in^2
Now, TSA = LSA + Base area = 216+9^2 = 297 in^2
a) It is given that the pyramid is smaller therefore, it will require lesser paint than the original pyramid ( The TSA of the smaller pyramid cannot be calculated as its dimentions are not given).
b) It can not be solved as dimensions are missing in the question.
However, the logic has been explained in the soluion one easily put values to find the solution.
It C)
This is because the sum of the two smaller sides in a triangle has to be larger than the bigger sides. 10+12=22.
22 is smaller than 24 which is the third side this no triangle is formed