So it states that the area of the rectangle is 56 cm, so all of it.
Given: 56 cm of rectangle
Unknown: find x
Length: 2 + x or x + 2
Width: 2x-5
Area = l * w
(x+2)(2x-5)
set x equal to 0
x+2=0 --> x=-2 2x-5=0 --> 2x=5 --> x = 5/2
so the answer we got was x=-2,5/2
we know that x cannot be negative because you can't measure with negative numbers, therefore, 5/2 is your answer
Answer: x=-9/2
Alternative Form: x= -4 1/2, x= -4.5
The formula for the area of the shaded region in the figure.
x² = 4py is mathematically given as
<h3>What is the formula for the area of the shaded region in the figure?</h3>
Parameters
Generally, the equation for the Area is mathematically given as
![& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\](https://tex.z-dn.net/?f=%26%20A%3D2%20%5Cint_%7B0%7D%5E%7B2%20%5Csqrt%7Bp%20h%7D%7D%5Cleft%28h-%5Cfrac%7Bx%5E%7B2%7D%7D%7B4%20p%7D%5Cright%29%20d%20x%20%5C%5C%5C%5C%26%20A%3D2%5Cleft%28h%20x-%5Cfrac%7Bx%5E%7B3%7D%7D%7B12%20p%7D%5Cright%5D_%7B0%7D%5E%7B2%20%5Csqrt%7Bp%20h%7D%7D%20%5C%5C%5C%5C%26%20A%3D2%5Cleft%5B%5Cleft%5Bh%202%20%5Csqrt%7Bp%20h%7D-%5Cfrac%7B1%7D%7B12%20p%7D%20%5Ccdot%282%20%5Csqrt%7Bp%20h%7D%29%5E%7B3%7D-0%5Cright%5D%5Cright.%20%5C%5C)
![&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h](https://tex.z-dn.net/?f=%26A%3D2%5Cleft%5B2%20h%5E%7B3%20%2F%202%7D%20%5Csqrt%7Bp%7D-%5Cfrac%7B8%28%5Csqrt%7Bp%7D%29%5E%7B3%7D%28%5Csqrt%7Bh%7D%29%5E%7B3%7D%7D%7B12%20p%7D-0%5Cright%5D%20%5C%5C%5C%5C%26A%3D2%5Cleft%5B2%20h%5E%7Bk%20%2F%202%7D%20%5Csqrt%7Bp%7D-%5Cfrac%7B2%7D%7B3%7D%20%5Csqrt%7Bp%7D%20%5Ccdot%20h%5E%7B3%20%2F%202%7D%5Cright%5D%20%5C%5C%5C%5C%26A%3D2%20%5Ctimes%20%5Cfrac%7B4%20%5Csqrt%7Bp%7D%20%5Ccdot%20h%5E%7B3%20%2F%202%7D%7D%7B3%7D%20%5C%5C%5C%5C%26A%3D%5Cfrac%7B8%7D%7B3%7D%20%5Ccdot%20%5Csqrt%7Bp%7D%20%5Ccdot%20%5Csqrt%7Bh%7D%20%5Ccdot%20h%20%5C%5C%5C%5C%26A%3D%5Cfrac%7B8%7D%7B3%7D%20%5Csqrt%7Bp%20h%7D%20%5Ccdot%20h)
In conclusion, the equation for the Area is
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Good luck finding this answer 211
