Answer:
526.12 μm³
Explanation:
Given that;
A typical human cell is approximately 10.00 μm in diameter &
enclosed by a membrane that is 8.000 nm thick.
What is the volume of the cell including the membrane?
First, let's determine the radius of the human cell=
=
=
= 5 μm
Now, the radius of the cell including the membrane
= 5 μm + 8.000 nm
= 5 μm + 0.008 μm
= 5.008 μm
The volume of the cell including the membrane is given by the formula:
526.1160731 μm³
526.12 μm³
1. where in a population:
p - the frequency of the <em>A</em> allele
q - the frequency of the <em>a</em> allele
- the frequency of the <em>AA</em> homozygous genotype
- the frequency of the <em>aa</em> homozygous genotype
2pq - the frequency of the <em>Aa</em> heterozygous genotype
A population at equilibrium will have the sum of all the alleles at the locus equal to 1.
2. Conditions:
A. The breeding population must be large
B. No natural selection
C. The mating must occur randomly
D. No mutations to cause changes in allelic frequency.
E. No changes in allelic frequency due to immigration or emigration.
3. By comparing the actual genetic structure of a population with what we would expect from a Hardy-Weinberg equilibrium, we can determine how much it deviates from the baseline provided by the mathematical model. Depending on how large the deviation is, one or more of the model's assumptions are being violated. Thus, we can attempt to determine which one.