The answer is (x-6)^2+(y+3)^2=4
Answer: (x-6)2 + (y+3)2=4
Step-by-step explanation:
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Answer:
tugukxukv upon cf undid
1
a+1=1
a=1-1
a=0
b^a which means:
b^0
whenever power is 0 answer is always one
so value of b^a is 1
