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Vlad1618 [11]
2 years ago
14

Can someone help pls

Mathematics
1 answer:
Alexxx [7]2 years ago
6 0

Answer:

A

Step-by-step explanation: because a b c are verticles of the fraction 1/3. So if we take 1/3 to a number line you are going to see the verticles of 1/3. Hope this helps.

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Answer 19277.1864781

Step-by-step explanation:

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Take away 6 from 8 times g
garri49 [273]

Answer:

8 - 6 = 2

Step-by-step explanation:

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3 0
1 year ago
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A rectangle is dilated by a factor of 1/5 the area of the new rectangle is 4 square yards what could be the dimensions of the or
Y_Kistochka [10]

Answer:

option (b) is correct.  

The dimensions of the original rectangle could be 4 × 5 yards

Step-by-step explanation:

Given : A rectangle is dilated by a factor of \frac{1}{5} the area of the new rectangle is 4 square yards .

We have to find  the dimensions of the original rectangle.

Dilation is a property to resize the figures without changing measures of angles. It just reduce the given figure if dilation factor is less than 1 and enlarge if dilation factor is greater than 1.

Since, given dilation factor is \frac{1}{5} , which is less than 1. Thus, the the resultant figure is smaller in size then the original

Original × dilation factor = new

Here, given figure is rectangle so,

Original rectangle  × dilation factor = new rectangle

Given :

new rectangle = 4 square yards

dilation factor = \frac{1}{5}

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Original rectangle = 4 × 5 square yards

Original rectangle = 20 square yards

Thus, option (b) is correct.  

Thus, the dimensions of the original rectangle could be 4 × 5 yards

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2. What is the length of the horizontal line segment joining points C(-9,205) and D(4,205)?​
arsen [322]

Answer:

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3 0
2 years ago
Let $M$, $N$, and $P$ be the midpoints of sides $\overline{TU}$, $\overline{US}$, and $\overline{ST}$ of triangle $STU$, respect
AysviL [449]

Answer:

<NPM + <NZM = 146°

Step-by-step explanation:

Given:

In triangle STU: M, N and P are the midpoints of the line TU, US and ST respectively.

Line UZ  is the altitude of the triangle STU

<TSU =71°, <TSU = 36°, <TUS = 73°

From the diagram:

N is the midpoint of line SU and M is the mid point of line UT.

∴ Line NM is parallel to line ST

P is the mid point of  line ST and M is the mid point of line UT

∴Line PM is parallel to line SU

N is the mid point of  line SU and P is the mid point of line ST

∴Line NP is parallel to line UT

Δ SPN = Δ STU = 36°

<SPN + <NPM + <MPT (Sum of angles in a triangle = 180°)

<UST = <MPT = 71°

36° + <NPM + 71° = 180°

<NPM + 107° = 180°

<NPM= 180°-107°

<NPM= 73°

In ΔSNZ, line SN = line NZ

∴ side SN = side NZ

< NSZ = <NZS = 71°

<MTZ = <MZT = 36°

<NZS + <NZM <MZT = 180°  (Sum of angles in a triangle = 180°)

71° + <NZM + 36° = 180°

107° + <NZM = 180°

<NZM = 180° - 107°

<NZM = 73°

<NPM + <NZM =73° + 73°

<NPM + <NZM = 146°

5 0
2 years ago
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