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USPshnik [31]
3 years ago
13

What is an equation of the line that passes through the points (−3,3) and (3,−7)?

Mathematics
2 answers:
MakcuM [25]3 years ago
7 0

Answer:

y=-\frac{5}{3}x-2

Step-by-step explanation:

line equation in general y = mx + b

m is the slope, and

b is the y-intercept

3=-3m+b

-7=3m+b

if we plus this two equations

3-7=2b

2b=-4

b=-2

3m=b-3=-5

m=-5/3

So,

y=-\frac{5}{3}x-2

Komok [63]3 years ago
4 0

Answer:

y=-\frac{5}{3} x+8

Step-by-step explanation:

Slope= \frac{y_{1}-y_{2}  }{x_{1} -x_{2} }

=\frac{3-(-7)}{-3-3}

=\frac{10}{-6}

=-\frac{5}{3}

So 3=-\frac{5}{3} *(-3)+b, b=8

So y=-\frac{5}{3} x+8

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12 * 100 = 1200/96 = 12.5 
Answer = 12.5%
You mulitply 12 by a hunndred, since a percent means "out of a hundred." Then, you divide that, by 96, since, you want to find the percent out of 96.

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Read 2 more answers
Determine the fraction of total interest owed using the rule of 78. After the six month of a 12 month loan, the numerator is: {(
Dima020 [189]

Answer:

The fraction of total interest owed is  \frac{57}{78}

The value of it to the nearest tenth is 73.1%

Step-by-step explanation:

Let us solve it using the rule of 78

∵ The loan = 12 month

∵ The numerator is after 6 month

- Substitute n by 1 in each bracket

∴ The numerator = {(1 + 11) + (1 + 10) + (1 + 9) + (1 + 8) + (1 + 7) + (1 + 6)}

∴ The numerator = {12 + 11 + 10 + 9 + 8 + 7}

∴ The numerator = {57}

∴ The numerator of the fraction is 57

∵ The denominator = {(n) + (n + 1) + (n + 2) + .......... + (n + 11)}

- substitute n by 1 in each bracket

∴ The denominator = {1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12}

∴ The denominator = {78}

∴ The denominator of the fraction is 78

The fraction of total interest owed is  \frac{57}{78}

Now find the value of the fraction

∵ The fraction = \frac{57}{78}

∴ Its value = 0.7307692308 × 100%

∴ Its value = 73.07692308%

- Round it to the nearest tenth

∴ Its value = 73.1%

The value of it to the nearest tenth is 73.1%

5 0
3 years ago
A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th
umka2103 [35]

Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of defectives among the 4 items sold.

The probability of a large lot of items containing defectives is, <em>p</em> = 0.09.

An item is defective irrespective of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 9 and <em>p</em> = 0.09.

The repair cost of the item is given by:

C=3X^{2}+X+2

Compute the expected cost of repair as follows:

E(C)=E(3X^{2}+X+2)

        =3E(X^{2})+E(X)+2

Compute the expected value of <em>X</em> as follows:

E(X)=np

         =4\times 0.09\\=0.36

The expected value of <em>X</em> is 0.36.

Compute the variance of <em>X</em> as follows:

V(X)=np(1-p)

         =4\times 0.09\times 0.91\\=0.3276\\

The variance of <em>X</em> is 0.3276.

The variance can also be computed using the formula:

V(X)=E(Y^{2})-(E(Y))^{2}

Then the formula of E(Y^{2}) is:

E(Y^{2})=V(X)+(E(Y))^{2}

Compute the value of E(Y^{2}) as follows:

E(Y^{2})=V(X)+(E(Y))^{2}

          =0.3276+(0.36)^{2}\\=0.4572

The expected repair cost is:

E(C)=3E(X^{2})+E(X)+2

         =(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73

Thus, the expected repair cost is $3.73.

4 0
3 years ago
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