Question

What is an equation of the line that passes through the points (−3,3) and (3,−7)?

Answer 1

Answer:

$y=-\frac{5}{3}x-2$

Step-by-step explanation:

line equation in general y = mx + b

m is the slope, and

b is the y-intercept

3=-3m+b

-7=3m+b

if we plus this two equations

3-7=2b

2b=-4

b=-2

3m=b-3=-5

m=-5/3

So,

$y=-\frac{5}{3}x-2$

Answer 2

Answer:

$y=-\frac{5}{3} x+8$

Step-by-step explanation:

Slope= $\frac{y_{1}-y_{2} }{x_{1} -x_{2} }$

=$\frac{3-(-7)}{-3-3}$

=$\frac{10}{-6}$

=$-\frac{5}{3}$

So $3=-\frac{5}{3} *(-3)+b$, b=8

So $y=-\frac{5}{3} x+8$