Answer:
It seems that your options aren't correct as the right answer is -5.3333... (recurring)
Step-by-step explanation:
1) 2x + 4 = 20 + 5x (subtract by the smallest unknown)
-2x -2x
2) 4 = 20 + 3x
-20 -20 (now subtract each side by 20 as we want to leave the unknown on one side and another number on the other side.
3) -16 = 3x (Divide each side by 3)
÷3 = ÷3
4) -5.33333... = x
<h3>Now we have found x but if you're unsure you can substitute to see if your answer is correct.</h3><h3>2 x -5.3333 + 4 = -6.6666</h3><h3>20 + 5 x -5.3333= -6.6665</h3><h3>Our answer is correct! (When answers are rounded, it is equal to the same thing).</h3>
<span>You run 0.5 miles every 3 minutes => 1 mile every 6 minutes. Your friend runs 2 miles every 14 minutes => 1 mile every 7 minutes. You run a whole number of miles every number of minutes that is a multiple of 6. Your freind runs a whole number of miles every number of minutes that is a multiple of 7 Then the least possible number of miles that you both run to end at the same time is the least common factor of 7 and 6 minutes. This is 7 * 6 = 42 minutes. You will have run 42 min / (6 miles/min) = 7 miles, and your friend will have run 42 min / (7 miles/min) = 6 miles</span>
Answer: 25x² - 64
<u>Step-by-step explanation:</u>
(5x + 8)(5x - 8)
= 5x(5x - 8) + 8(5x - 8)
= 25x² - 40x + 40x - 64
= 25x² + 0x - 64
= 
NOTE: descending powers means the biggest exponent goes first, then the next biggest exponent, etc.
For example: x⁴ then x³ then x² then x then the number (which is actually x⁰)
Your answer would be the last option, (6x² - 5)(x² + 2).
This is because when you expand it, you get:
6x² × x² = 6x⁴
6x² × 2 = 12x²
-5 × x² = -5x²
-5 × 2 = -10
Which are all the correct terms.
I hope this helps!
9514 1404 393
Answer:
P(F|A) = 35%
Step-by-step explanation:
P(F|A) = P(F&A)/P(A) = 7%/20% = 0.35
P(F|A) = 35%
_____
The given numbers will let you fill in a table for all of the categories of workers. However, it turns out this question can be answered using only the numbers given in the problem statement.