Answer:
b>44
Step-by-step explanation:
12/5<b-8/15
switch sides b-8/15>12/5
multiply both sides by 15 15(b-8)/15>12*15/5
simplify b-8>36
add 8 to both sides b-8+8>36+8
simplify
b>44
Answer:
<u>40%</u>
Step-by-step explanation:
Working out percentages
168 of 420 can be written as:
168
/420
420
To find percentage, we need to find an equivalent number with denominator 100. Multiply both numerator & denominator by 100
=(168/420)*(100)
= <u>40
/100
</u>
Therefore, the answer is <u>40%
</u>
If you are using a calculator, simply enter 168÷420×100 which will give you 40 as the answer.
1 mile =1.60934km
So the have travelled about 1 mile.
Answer:
Lamda= 4 students/min, µ= 5 students/min
P= Lamda/µ= 4/5= 0.8
a.) Probability that system is empty= P0= 1-P= 1-0.8= 0.2
b.) Probability of more than 2 students in the system= ∑(n=3 to inf) P^n*P0= (1-P)*(1/(1-P) – (1-P) –(1-P)*P –(1-P)*P^2)= (.2)*(5- - .2 - (.8)*.2 – (.2)*.8^2))= 0.848
Probability of more than 3 students in the system= ∑(n=4 to inf) P^n*P0= (1-P)*(1/(1-P) – (1-P) –(1-P)*P –(1-P)*P^2 – (1-P)*P^3)= 0.768
c.) W(q)= Waiting time in Queue= lamda/µ(µ- lamda)= 4/5(1)= 0.8 minutes
d.) L(q)= lamda*W(q)= 4*.8= 3.2 students
e.) L(System)= lamda/(µ-lamda)= 4 students.
f.) If another server with same efficiency as the 1st one is added, then µ= 6 sec/student= 10 students/min.
P= 4/10= 0.4
Probability that system is empty= P0= 1-.4= 0.6
W(q)= 4/10(10-4)= 0.0667 minutes
L(q)= Lamda*W(q)= 4*.0667=0.2668
L(system)= Lamda/(µ-lamda)= 4/6= .667
Step-by-step explanation:
Answer:
Brainly User
The equation given is f(x) = x^2 - 12x + 27
Based on its form, it is a parabola. First, factor the quadratic equation:
f(x) = (x-9) (x-3)
Plot in the x-y plane, assign values of x and solve for the values of y.
x y
1 16
2 7
3 0
0 27
-1 40
-2 55
-3 72
