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OLEGan [10]
3 years ago
14

aria paid 24,500 for her car. the value of the car decreases by 10.4% each year. create an equation that represents the value of

v, the car, after t, years.
Mathematics
2 answers:
Nina [5.8K]3 years ago
8 0

Answer:

i have no clue

Step-by-step explanation:

lol

White raven [17]3 years ago
5 0

Answer:

$2623.5

Step-by-step explanation:

We would apply the formula for exponential decay which is expressed as

A = P(1 - r)^ t

Where

A represents the value of the car after t years.

t represents the number of years.

P represents the value of the car.

r represents rate of decay.

From the information given,

P = 24500 dollars

r = 14.75% = 14.75/100 = 0.1475

t = 14 years

Therefore

A = 24500(1 - 0.1475)^14

A = 24500(0.8525)^14

A = $2623.5

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C = COMPOUND INTEREST
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3 years ago
A used car dealer has 30 cars and 10 of them are lemons (i.e.~ mechanically faulty used cars), and you don't know which is which
Triss [41]

Answer: Hence, the probability that he will get at least one lemon is 0.70.

Step-by-step explanation:

Since we have given that

Number of cars = 30

Number of lemon cars = 10

Number of other than lemon cars = 30-10 = 20

According to question, he bought 3 cars,

we need to find the probability that you will get at least one lemon.

So, P(X≤1)=1-P(X=0)=1-P(no lemon)

Here, P(no lemon ) is given by

\dfrac{20}{30}\times \dfrac{20}{30}\times \dfrac{20}{30}=(\dfrac{20}{30})^3

so, it becomes,

P(X\geq 1)=1-(\dfrac{20}{30})^3=1-(0.67)^3=0.70

Hence, the probability that he will get at least one lemon is 0.70.

5 0
3 years ago
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lys-0071 [83]
The answer is A 
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7 0
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Suppose the half-life of a certain radioactive substance is 12 days. Find the time when there will be 20% of the initial substan
vazorg [7]

Answer: 2.4% I think

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7 0
3 years ago
What is the solution to the system of equations below?
Karolina [17]

Answer:

The solution is the point (18,0)

Step-by-step explanation:

we have

y=-\frac{1}{3}x+6 -----> equation A

y=\frac{1}{3}x-6 -----> equation B

Solve the system by substitution

substitute equation B in equation A

\frac{1}{3}x-6=-\frac{1}{3}x+6

solve for x

Adds (1/3)x both sides

\frac{1}{3}x-6+\frac{1}{3}x=6

\frac{2}{3}x-6=6

Adds 6 both sides

\frac{2}{3}x=6+6

\frac{2}{3}x=12

x=12(3)/2\\x=18

<em>Find the value of y</em>

substitute the value of x in equation A or equation B

y=-\frac{1}{3}(18)+6=0

therefore

The solution is the point (18,0)

3 0
3 years ago
Read 2 more answers
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