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salantis [7]
3 years ago
6

Point S has the coordinates (6, –4)

Mathematics
2 answers:
Anni [7]3 years ago
8 0

Answer:

C:T

Step-by-step explanation:

Trust me on this, also can I have brainiest please?

Hope you do well! :D

Sidana [21]3 years ago
3 0
Their is no “ R, A, T, U” on the grid?
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a woman jogging at 6mi/hr passes a man biking in the opposite direction at 12mi/hr. If they maintain their speeds, how far from
s344n2d4d5 [400]
The woman is moving at 6mi/hr which means 1mi per 10 minuets because 1 hour = 60 minuets and she is moving 6 mi every 60 minutes which means 1 mi every 10 minuets , same thing for that man 12 mi every hour = 2 mi every 10 minuets , and because of the opposite direction we will add 2 + 1 = 3mi after 10 minuets. I hope that helped u a little bit.
7 0
3 years ago
Use the image below to answer the following question:
nikdorinn [45]

Answer:

The ratios are both identical. (4 over 5 and 4 over 5)

Step-by-step explanation:

Th picture below represent the image you are referring.

sin x = opposite / hypotenuse

opposite side = 4

hypotenuse = 5

sin x° = 4/5

cos y° = adjacent/hypotenuse

adjacent = 4

hypotenuse = 5

cos y° = 4/5

The ratios are both identical (4 over 5 and 4 over 5)

6 0
3 years ago
Read 2 more answers
Combine the like terms<br><br> 1.4b-<img src="https://tex.z-dn.net/?f=3b%5E%7B2%7D" id="TexFormula1" title="3b^{2}" alt="3b^{2}"
WINSTONCH [101]

Answer:

If your asking us to just combine like terms it would be -3b^2-2b^2+1.4b+4c+c

but if your asking us to answer the question it would be -5b^2+1.4b+5c

Hope I helped :)

4 0
3 years ago
36a^2+24b^2=12( +2b^2)
vlabodo [156]
The blank space is found by dividing 36a^2 by 12, which is equal to 3a^2
To get to this answer you need to
1. divide the both sides of the equation by 12.
2. subtract 2b^2 from both sides. 
You will see that the blank space equals 3a<span>^2 then</span>
7 0
3 years ago
Please explain step by step
Alja [10]

Let's find the value of x

Since the sum of internal angles of a triangle is 180°

therefore,

\hookrightarrow \: (2x - 2) \degree + (x + 5) \degree + 90 \degree = 180 \degree

\hookrightarrow \: 2x - 2 \degree + x + 5\degree  = 180\degree - 90\degree

\hookrightarrow \: 3x + 3\degree = 90\degree

\hookrightarrow \: 3(x + 1) = 3(30)

\hookrightarrow \: x + 1\degree = 30\degree

\hookrightarrow \: x = 29\degree

4 0
3 years ago
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