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3 years ago

Who know the answer? Pls

Mathematics

2 answers:

Iteru [2.4K]3 years ago

6 0

Answer:

Exponential Growth

Step-by-step explanation:

The number of bacteria is always growing, because it/they is/are reproducing

baherus [9]3 years ago

4 0

Answer: Exponential growth

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Help me out pleaseeee

gladu [14]

4x - y = 5 --> 4x = y + 5

substitute

4x + 4y = -4

(y + 5) + 4y = -4

5y + 5 = -4

5y = -9

y = -1.8

solve x

4x = y + 5 = -1.8 + 5 = 3.2

x = 3.2/4 = 0.8

6 0

2 years ago

Please help! And I need the steps too!

fomenos

Answer:

-25

Step-by-step explanation:

Step 1: 2-9-5-3-2- $2^{3}$

Step 2: 2-9-5-3-2-8

Step 3: -25

7 0

3 years ago

Solve the system of equations by substituion,<br> -5x + y = 3<br> 7.5x - 1.5y = 3

Naya [18.7K]

The first equation, make the y as the subject. y = 3 + 5x, then substitute y in the second equation and you will get the value of x. then, substitute the x in the first equation (y = 3 + 5x)

5 0

3 years ago

What is the function graph if both the domain and range is (−∞, ∞)

velikii [3]

Answer:

(−∞, ∞) and (−∞, ∞)

Step-by-step explanation:

One example (of many) might be y = 2x. The domain and range of this function are (−∞, ∞) and (−∞, ∞).

7 0

3 years ago

Consider the implicit differential equation <img src="https://tex.z-dn.net/?f=%2849%20y%5E%7B3%7D%20%2B%2045%20xy%29%20dx%20%2B%

BaLLatris [955]

We're looking for an integrating factor $\mu(x,y)=x^py^q$ such that

$\mu\underbrace{(49y^3+45xy)}_M\,\mathrm dx+\mu\underbrace{(98xy^2+50x^2)}_N\,\mathrm dy=0$

is exact, which would require that

$(\mu M)_y=(\mu N)_x$
$(49x^py^{q+3}+45x^{p+1}y^{q+1})_y=(98x^{p+1}y^{q+2}+50x^{p+2}y^q)_x$
$49(q+3)x^py^{q+2}+45(q+1)x^{p+1}y^q=98(p+1)x^py^{q+2}+50(p+2)x^{p+1}y^q$
$\implies\begin{cases}49(q+3)=98(p+1)\\45(q+1)=50(p+2)\end{cases}\implies p=\dfrac52,q=4$

You can verify that $(\mu M)_y=(\mu N)_x$ if you'd like. With the ODE now exact, we have a solution $F(x,y)=C$ such that

$F_x=\mu M$
$F=\displaystyle\int(49y^3+45xy)x^{5/2}y^4\,\mathrm dx$
$F=10x^{9/2}y^5+14x^{7/2}y^7+f(y)$

$F_y=\mu N$
$50x^{9/2}y^4+98x^{7/2}y^6+f'(y)=98x^{7/2}y^2+50x^{9/2}y^4$
$f'(y)=0$
$\implies f(y)=C$

and so the general solution is

$F(x,y)=10x^{9/2}y^5+14x^{7/2}y^7=C$

8 0

3 years ago