Heyaaa, can you help me out? I'm not exactly sure how to go about solving this.
2 answers:
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Answer:
Midpoint = (3.5, 4.5)
Perpendicular bisector = y = x +
Step-by-step explanation:
[] We can solve this using the midpoint formula:
-> See attached
[] Plug-in our coordinates and solve:
[] Now we will find the slope to solve for the perpendicular bisector.
-> We will use slope-intercept form, see attached
-> The slopes of two perpendicular lines are negative reciprocals of each other, so will be the slope of or perpendicular bisector
-> Now we can solve for the equation by using y – y1 = m ( x – x1), were y1 and x1 are the coordinates of our midpoint
y - 4.5 = (x-3.5)
y - 4.5 = x-
y = x-
+ 4.5
y = x +
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
Answer:
- P(t) = 100·2.3^t
- 529 after 2 hours
- 441 per hour, rate of growth at 2 hours
- 5.5 hours to reach 10,000
Step-by-step explanation:
It often works well to write an exponential expression as ...
value = (initial value)×(growth factor)^(t/(growth period))
(a) Here, the growth factor for the bacteria is given as 230/100 = 2.3 in a period of 1 hour. The initial number is 100, so we can write the pupulation function as ...
P(t) = 100·2.3^t
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(b) P(2) = 100·2.3^2 = 529 . . . number after 2 hours
__
(c) P'(t) = ln(2.3)P(t) ≈ 83.2909·2.3^t
P'(2) = 83.2909·2.3^2 ≈ 441 . . . bacteria per hour
__
(d) We want to find t such that ...
P(t) = 10000
100·2.3^t = 10000 . . . substitute for P(t)
2.3^t = 100 . . . . . . . . divide by 100
t·log(2.3) = log(100)
t = 2/log(2.3) ≈ 5.5 . . . hours until the population reaches 10,000
