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Butoxors [25]
4 years ago
9

Linda had 42 fliers to post around town. Last week, she posted 2/3 of them. This week she posted 5/7 of the remaining flires. Ho

w many fliers has she still not posted?
Mathematics
2 answers:
DENIUS [597]4 years ago
8 0

Answer:

4

Step-by-step explanation:

Linda has 42 and posts 2/3 the first day

2/3 of 42 is 28

this week she has 14 left and hands out 5/7 of them

5/7 of 14 is 10

In total Linda has posted 38 fliers which means there are 4 left

butalik [34]4 years ago
8 0

Answer:

4

Step-by-step explanation:

Last week she posted 2/3 of the 42 fliers.  This means she posted (2/3)*42 fliers.

(2/3)*42

84/3

28

So she posted 28 last week.

So of the 42, 42-28=14 remain

This week she posted 5/7 of the remaining fliers.

So she posted 5/7 of the 14 that remainder. This means she posted (5/7)*14 fliers.

(5/7)*14

70/7

10

So she posted 10 this week.

So of the 42, 42-28-10=4 remain.

She hasn't posted 4 fliers.

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parallelogram

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PLEASE HELP, GOOD ANSWERS GET BRAINLIEST.
irina [24]
<span>1. We analyze the limit by approaching it from both the left and the right.
From the left: f(x) = x + 10 (for x < 8), as x --> 8, f(x) --> 18
From the right: f(x) = 10 - x (for x >= 8), as x --> 8, f(x) --> 2
Since the limits on either side do not converge to the same point, the limit does not exist (this is choice C).

2. </span>Using a similar approaching as in #1:
<span><span>From the left: f(x) = 5 - x (for x < 5), as x --> 5, f(x) --> 0
At x = 5 itself: f(x) = 8
From the right: f(x) = x + 3 (for x > 5), as x --> 5, f(x) --> 8</span>
Although the value at x = 5 matches with the limit when approaching from the right, the limit when approaching from the left doesn't match, so the limit does not exist (choice D).

3. </span><span><span>From the left: f(x) = 5x - 9 (for x < 0), as x --> 0, f(x) --> -9
From the right: f(x) = |2 - x| (for x >= 0), as x --> 0, f(x) --> 2
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4. lim 1/(x - 4) as x -->4-
If we are approaching x = 4 from the left, we can test values such as 3, 3.9, 3.99, 3.999, approaching 4. For x = 3, f(x) = -1. For x = 3.9, f(x) = -10. For x = 3.99, f(x) = -100. For x = 3.999, f(x) = -1000. This shows that the value continues to go towards negative infinity.
If we were to graph these 4 points on the Cartesian plane, it would also show a curve to slopes downwards to negative infinity, with the vertical asymptote at x = 4. The correct answer is Choice C) -∞ ; x = 4.

5. </span>f(x) = (x+1)(x-1) / [(x+1)(x-2)] is an example of a function with both a removable and non-removable discontinuity.
In this case, because x+1 cancels out from the numerator and denominator, it results in a hollow or missing point (removable) discontinuity at x = -1. This means that the limit still exists as x --> -1. On the other hand, x = 2 is a non-removable discontinuity, since it cannot be cancelled out, and it will be an asymptote.
4 0
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Step-by-step explanation:

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cos a = -1/2

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\tan(a )  =  \sqrt{3}

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