All categories

3 years ago

Why can't i get my answers

Mathematics

2 answers:

Komok [63]3 years ago

6 0

Answer:

What answer do you need or u want someone to answer?

Grace [21]3 years ago

5 0

What do you mean you can’t get your answers ?

You might be interested in

Which polynomial is in standard form?

kirill115 [55]

Answer:

$2x^3 +4x^2 -7x+5$

Step-by-step explanation:

Polynomial $2x^3 +4x^2 -7x+5$ is in standard form as it is written in descending order of their powers.

8 0

3 years ago

2/5(d−10)−2/3(d+6) is

MissTica

Remove parentheses
2/5 • d-10 - 2/3 • d+6

calculate
2/5d-4 - 2/3d-4

the answer
-4/15d-8

3 0

4 years ago

I need to find weather the ordered pair is a solution of the system of linear equation

Makovka662 [10]

In exercise 3 (2,6) means that x=2 and y=6
so you have to check that if this values of x and y satisfied the given equation,
by showing that the left hand side = the right hand side ..

5 0

3 years ago

The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers

stealth61 [152]

Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

Confidence interval for female expenditure is ($49.18, $69.30)

Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

Female expenditure

Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

(b) Male: Error margin = (t-value × sd)/√n

Degree of freedom = n-1 = 40-1= 39. t-value corresponding to 39 degrees of freedom and 99% confidence level is 2.708

Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

Female

Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

Confidence Interval (CI) = (mean + or - error margin)

CI = 121.4 + 15.00 = $136.40

CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

7 0

4 years ago

Find the P-value for the indicated hypothesis test with the given standardized test statistic, z. Decide whether to reject H0

Leviafan [203]

Answer: We do not reject the null hypothesis.

Step-by-step explanation:

When the p-value is greater than the significance level , then we do not reject the null hypothesis or if p-value is smaller than the significance level , then we reject the null hypothesis.

Given : Test statistic : $z = -2.28$

Significance level : $\alpha=0.02$

By using the standard normal distribution table ,

The p-value corresponds to the given test statistic ( two tailed ):-

$2P(Z>|z|)=2P(Z>2.28)=0.0226$

Since the p-value is greater than the significance level of 0.02.

Then , we do not reject the null hypothesis.

8 0

4 years ago