Answer:
a) 47.55
b) 58
c) 47.88
Step-by-step explanation:
Given that the size of the orders is uniformly distributed over the interval
$25 ( a ) to $80 ( b )
<u>a) Determine the value for the first order size generated based on 0.41</u>
parameter for normal distribution is given as ; a = 25, b = 80
size/value of order = a + random number ( b - a )
= 25 + 0.41 ( 80 - 25 )
= 47.55
<u>b) Value of the last order generated based on random number (0.6)</u>
= a + random number ( b - a )
= 25 + 0.6 ( 80 - 25 )
= 25 + 33 = 58
<u>c) Average order size </u>
= ∑ order 1 + order 2 + ----- + order 10 ) / 10
= (47.55 + ...... + 58 ) / 10
= 478.8 / 10 = 47.88
4/3
Remember if two lines are perpendicular, the product of their slopes are -1
Step-by-step explanation:
f(x)+g(x)=(2x^2 + 5x +6) + (3x^2 +4x - 10)
Combine like terms
5x^2 + 9x -4
f(x)-g(x)=(2x^2 + 5x +6) - (3x^2 +4x - 10)
Distribute the negative
(2x^2 + 5x +6) + (-3x^2 -4x + 10)
Combine like terms
-x^2 +x +16
35% Just move the decimal place forward two places. That's how i LEARNED IT
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