Answer: 36 oz
Step-by-step explanation:
4.20 its more but you get 6 oz more
Answer:
Step-by-step explanation:
Total number of antenna is 15
Defective antenna is 3
The functional antenna is 15-3=12.
Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.
So,
We line up the 13 good ones, and see where the bad one will fits in
__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __
Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.
Then,
There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement
ⁿCr= n!/(n-r)!r!
The number of arrangement is
14C3=14!/(14-3)!3!
14C3=14×13×12×11!/11!×3×2
14C3=14×13×12/6
14C3=364ways
Answer:
5 is D
6 is C
Step-by-step explanation:
Define:
Equilateral - All sides and angles are congruent
Isosceles: Two congruent sides and two congruent angles
Scalene: No congruent sides or angles
Right triangle: A triangle with a right angle ( note that a right angle has a measure of 90 degrees )
obtuse triangle: A triangle with an obtuse angle ( obtuse angles have a measure of more than 90 degrees. )
Acute triangle : A triangle with an acute angle ( an acute angle has a measure of less than 90 degrees )
Answer:
the triangle shown in # 5 has a right angle and 2 congruent sides and angles
Therefore the triangle in #5 is a right isosceles
The triangle shown in #6 has an angle with a measure that is more than 90 degrees and have no congruent sides or angles therefore the triangle in #6 is an obtuse scalene.
We are given a relationship between the sides of a rectangle, that is, the length of one of its sides is 5 less two times its width, and we are asked to find an expression for the area. Let's remember that the area of a rectangle is equal to the product of the length of its side by its width. Let "w" be the length of the rectangle and "L" its lenght, then the area is given by the following formula:
We can use the relationship given in the problem, that is, its length being five less two times its width, that is:
Replacing in the formula for the area we get:
Now we use the distributive law:
