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3 years ago

11

What is 23 + | 3-2 | ?

2 answers:

ValentinkaMS [17]3 years ago

6 0

Answer:

24

Step-by-step explanation:

3 - 1 equal 1 plus 23 equal 24

ss7ja [257]3 years ago

3 0

Answer:

Step-by-step explanation:

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Suppose that the functions u and w are defined as follows.

jasenka [17]

Answer(there are assumptions for this answer that you need to confirm and look at):

Assumptions: $u(x)=x^2+3$ and $w(x)=\sqrt{x+2}$

Answer if the operation is multiplication:

If you meant a closed dot which is the symbol for multiplication.

$(u \cdot w)(2)=14$

$(w \cdot u)(2)=14$

Answer if the operation is composition:

If you meant an open dot which is the symbol for composition.

$(u \circ w)(2)=7$

$(w \circ u)(2)=3$

Note: I don't know if you actually meant $w(x)=\sqrt{x+2}$ or if $w(x)=\sqrt{x}+2$ . Please let me know one way or the other.

Step-by-step explanation:

If we assume the functions are:

$u(x)=x^2+3$

$w(x)=\sqrt{x+2}$

$u \cdot w=w \cdot u$ since multiplication is commutative.

$u(2)=2^2+3$

$u(2)=4+3$

$u(2)=7$

$w(2)=\sqrt{2+2}$

$w(2)=\sqrt{4}$

$w(2)=2$

We are asked to find $(u \cdot w)(2)$ and $(w \cdot u)(2)$ .

The order doesn't matter in multiplication.

$(u \cdot w)(2)$

$u(2) \cdot w(2)$

$7 \cdot 2$

$14$

$(w \cdot u)(2)$

$w(2) \cdot u(2)$

$2 \cdot 7$

$14$

Now you might have meant composition which symbolized with an open circle, not a closed one.

$(u \circ w)(2)$

$u(w(2))$

$u(2)$ since $w(2)=2$

$2^2+3$

$4+3$

$7$

$(w \circ u)(2)$

$w(u(2))$

$w(7)$ since $u(2)=7$

$\sqrt{7+2}$

$\sqrt{9}$

$3$

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3 years ago

How much less is 17km than 24.6km?

tatuchka [14]

24.6-17= 7.6 (km) i think so

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2 years ago

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9- 3x - (-8y) + 9x - y Solve pleaseee

Yuki888 [10]

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3 years ago

Help!! WILL GIVE BRAINLIEST!!! What is the range of possible sizes for side x? Please explain about the rule as well.....

yaroslaw [1]

Answer:

0.2 < x < 11.8

Step-by-step explanation:

The triangle inequality theorem states that the sum of any two sides of a triangle must be greater than the third side, for it to form a triangle. So, we can set up 3 equations, x + 5.8 > 6, 5.8 + 6 > x, and x + 6 > 5.8. This solves out to x > 0.2, x < 11.8, and x > -0.2. We can disregard that last one, because a side can't be negative. Therefore, we know the possible range of values for x.

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3 years ago

What is another way to write the expression t⋅(14−5) ? (t⋅14)⋅5 t⋅14−5 (t⋅14)−5 (t⋅14)−(t⋅5)

Finger [1]

Another way to write the expression the answer is this (t.14)-(t.5)

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3 years ago

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